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#1 |
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Join Date: Sep 2018
Location: North Texas
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How do folks handle vertical jumping in TFT?
The rules are oddly silent on this, though TBH, it really doesn't seem to come up much in play so perhaps it isn't very odd after all.
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“No matter how subtle the wizard, a knife between the shoulder blades will seriously cramp his style.” -Vladimir Taltos |
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#2 |
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Join Date: Sep 2023
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Yes, I think this ends up tying into the Jump Spell thread nicely. Humans don't tend to jump very high. Long jumping takes a bit of speed and strength. Some creatures have great natural jumping abilities. IMO to get anywhere high, a character would need to use Climbing talent or need to become a cat. Acrobatics could be helpful for a lightly armored character to Parkour climb.
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#3 | |
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Join Date: Sep 2018
Location: North Texas
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Quote:
Maybe the default increment should be a half-hex UP and a full hex DOWN for 2 MA? Then ACROBATICS might double that baseline? Curious if others have tried to address in their house-rules.
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“No matter how subtle the wizard, a knife between the shoulder blades will seriously cramp his style.” -Vladimir Taltos |
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#4 |
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Join Date: Aug 2004
Location: Pacheco, California
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A vertical jump is simply twice a horizontal jump as per ITL 104.
So (while not engaged) jumping up two feet costs 3 MA and is automatic. Jumping up 4 feet is 4 MA and requires the five dice throw, and 6 feet is 8 dice and so on. Acrobatics of course helps here.
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-HJC |
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#5 |
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Join Date: Sep 2018
Location: North Texas
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Not sure where you're reading that. I see nothing about vertical height on pg 104.
__________________
“No matter how subtle the wizard, a knife between the shoulder blades will seriously cramp his style.” -Vladimir Taltos |
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#6 | |
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Join Date: Sep 2023
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Quote:
Jumping over X hex(es) and landing in the next one is: 1-Hex jump horizontal is 3 MA and automatic save 2-Hex jump horizontal is 4 MA and 5vs(ST+DX) 3-Hex jump horizontal is 4 MA and 8vs(ST+DX) assumption with so on 4-Hex jump is 4 MA and 11vs(ST+DX) This is a little bit of a change up from the old Advanced Melee book, p.5. |
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#7 |
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Join Date: Oct 2015
Location: New England
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I’ve read that the average NBA vertical leap is 28 inches, which is a bit over a half-hex.
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#9 |
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Join Date: Oct 2015
Location: New England
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That’s still not very clear. Can you elaborate?
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#10 |
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Join Date: Aug 2004
Location: Pacheco, California
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Maximum length jump is at 45 degrees and reaches a quarter of the jump length in height. So rotate that vector and put all of jump into height instead.
For example, a one second duration maximum length jump is 5 m/s up and 5 m/s along the length and hence covers 5 m in that second. In the half second to reach maximum height you travel d = 0.5 * a * t^2 = .5 * 10 * (0.5)^2 = 1.25 meters in height (or a fourth the length as expected).
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-HJC Last edited by hcobb; 09-22-2023 at 06:25 AM. |
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