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#1 | ||
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Join Date: Jul 2008
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People have tried many times to puzzle them out, usually primarily from the beam weapon figures. I think there might be a revealing post from the author somewhere on the forum as well. (Possibly in connection with the beam weapon design Pyramid article instead of Spaceships, but you can work between the two...)
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I don't know any 3e, so there is no chance that I am talking about 3e rules by accident. |
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#2 | |||
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Join Date: Oct 2008
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Compare that to the other source without numbers: ultratech where the difference between TL 9 and TL 10 is *10 and the addition of ^ to the fusion plant multiples by *5 again and the TL 9-12 is *100(the same for TL 9-11^) Also there you need *50 the mass to produce the same energy with solar panel than TL 12 antimatter. But yes, the only "real" numbers we have on power are the beam weapon power numbers in spaceships. The power situation is one of the great annoyances I have with gurps tech supplements. |
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#3 |
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Join Date: Jul 2008
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...Does this have anything to do with the subject of how much hydrogen you get from electrolysis of water?
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I don't know any 3e, so there is no chance that I am talking about 3e rules by accident. |
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#4 |
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Join Date: Oct 2008
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It would indicate that the output is relative to the mass fraction and the capacity as given for chemical refinery is the input mass, as you were replying to just keeping the hydrogen question.
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#5 | |
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Untagged
Join Date: Oct 2004
Location: Forest Grove, Beaverton, Oregon
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Reliability, commonality/cost of fuel, radiation/toxic dangers, complexity, hassle of maintenance, etc.
__________________
Beware, poor communication skills. No offense intended. If offended, it just means that I failed my writing skill check. |
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#6 | |
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Join Date: Oct 2008
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As example quite many of the warships in the SS series have two reactors. Being able to reduce that to one or less would be a tremendous boost for many of them. In addition the higher TL ones with force screens could run with the improved DR always in combat. Basically at minimum a ship with a reactionless drive has 6 modules: 3 armor, 1 control, 1 drive, 1 reactor, leaving 14 modules for other stuff. Thus a reduction in power density where you can reduce one module you get 7% more capacity, if you can reduce two you get almost 15% increase. |
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#7 | |||
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Join Date: Aug 2010
Location: The Land of Enchantment
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#8 | ||
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Join Date: Jul 2008
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Converting between Power Points and Power Cells/time is actually very doable by way of the beam weapon design article. Quote:
The issue is how efficiently you can contain antimatter. If your containment is several orders of magnitude heavier than the material contained, you're losing a lot off the theoretical density advantage of antimatter. (Though the relatively short endurance of AM reactors in Spaceships suggests that it's not extending that advantage anyway.)
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I don't know any 3e, so there is no chance that I am talking about 3e rules by accident. |
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#9 | |
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Untagged
Join Date: Oct 2004
Location: Forest Grove, Beaverton, Oregon
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Antimatter is nice for how simple it is to explain to us laymen. But I doubt it will ever be used for energy storage in our universe or reasonable hard science fiction setting.
__________________
Beware, poor communication skills. No offense intended. If offended, it just means that I failed my writing skill check. |
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#10 | |
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Join Date: Jun 2013
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Solar TL7 TL8 TL9 TL10 PP 1 1 1 1 kW/ton 1 2 5 10 Fuel Cell TL7 TL8 TL9 TL10 PP (endurance) 1 (3h) 1 (6h) 1 (12h) 1 (24h) kW/ton (end) 5 (4h) 10 (4h) 20 (4h) 20 (8h) Fission TL8 TL9 TL10 PP (end) 1 (25y) 1 (50y) 1 (100y) kW/ton (2y) 15 30 100 *Under my system, refueling the reactor is only 10% of the initial cost. Long-endurance reactors are also available, which have 1/3rd normal output but a 100 year endurance and cost 50% to refuel. Fusion TL9 TL10 TL11 TL12 PP (end) 2 (50) 2 (200) 2 (600) 2 (1200) kW/ton (200y) 100 200 500 500 From weapons, 1 PP for SM+5 can power a 10 MJ weapon indefinitely. As this weapon only fires every 20 seconds, that's 500 kW. An SM+5 vessel weighs 30 tons, so you're looking at around 1 PP = 15 kW/ton. Of course, that's output, where you're going to see some efficiency drops. The minimum here is actually 1 PP = 30 kW/ton, assuming the Improved versions of beam weapons have close to 100% efficiency. From a refinery, 1 PP for SM+5 can process 0.5 tons of water into rocket fuel every hour. Hydrogen has a heat of combustion of 141.8 MJ/kg (HHV); as there are around 907.185 kg/ton, that means we're dealing with around 600 kW/ton. Again, this is output, so there should be some efficiency losses along the way. This also helps demonstrate why the rate at which the refinery produces rocket fuel is probably broken - by the above, you'd need around 3 fusion reactors to run that thing! Using the SS7 fix, with hours replaced by days, results in around 25 kW/ton, which is pretty close to the output of Improved beam weapons, above. Last edited by Varyon; 10-29-2015 at 10:15 AM. |
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