12-05-2005, 01:33 PM | #1 | |||
Wielder of Smart Pants
Join Date: Aug 2004
Location: Ventura CA
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Planet Destroyers
From more powers excerpts
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I am not saying that this is really necessary, but it is trivial to figure out. |
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12-05-2005, 08:37 PM | #2 | |
Join Date: Sep 2005
Location: Topeka, Kansas
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Re: Planet Destroyers
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So, it does matter and they DO state the damage in Dark Empire of the Death Star's damage (being essentially 20D, death star scale), just IMO when you have a 'plot device' you don't need to figure out the damage. You can't fight the death star. You must circumvent it, like they did for plot. :)
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Cleopatra: Whenever she assigned me to the switch, was that Voice, or was Raina influencing her thinking? Because, I mean, if it was Raina, she got inside my head and decided that I would screw it up. |
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12-06-2005, 10:57 AM | #3 |
Join Date: Nov 2005
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Re: Planet Destroyers
Gotta agree with you there unless your game is all about Planet-Destroying conflicts, most of the time if my players asked "How much damage is that weapon doing", my answer would be "Enough....".
A Single weapon capable of destroying a planet in a single shot would be prohbitively expensive, your probably looking at Trillions of Dice of Damage with a significant Armour Piercing ability(I mean what's a planets DR)... |
12-06-2005, 11:13 AM | #4 |
Join Date: Nov 2005
Location: Montreal, Canada.
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Re: Planet Destroyers
I believe that "Planet-Destroyers" weapons are plot devices. They work when they need to work and they fails when they need to fail. Simple.
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12-06-2005, 01:06 PM | #5 | |||
Wielder of Smart Pants
Join Date: Aug 2004
Location: Ventura CA
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Re: Planet Destroyers
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12-06-2005, 07:43 PM | #6 | |
Join Date: Sep 2005
Location: Topeka, Kansas
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Re: Planet Destroyers
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Well, again, Dark Empire stated that Planetary Shields DO exist, and they CAN stop the Death Star from atomizing the planet like it did Alderaan... BUT, the Death Star will still partially penetrate the shield from overloading it, then the remaining energy of the laser will ignite and burn off the atmosphere. Pain and burning agony. Seems that atomization of the planet thing isn't so bad, is it? It DOESNT work on gas giants... only on terrestrial type planets. Simple enough. Then, if you use it against something smaller than a planet, well... it's dead.
__________________
Cleopatra: Whenever she assigned me to the switch, was that Voice, or was Raina influencing her thinking? Because, I mean, if it was Raina, she got inside my head and decided that I would screw it up. |
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12-06-2005, 09:32 PM | #7 | ||
Join Date: Oct 2005
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Re: Planet Destroyers
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Even in a Star Wars campaign, if planetary shields that almost block it exist (perhaps allowing people in fortified bunkers to survive) it should be theoretically possible to build such a battle station. Or a technological weapon like the death star could coexist with supernatural powers like those in Lensman, which could potentially defend against it. And why would you say it doesn't work AT ALL on Gas Giants? It could do damage without destroying them. |
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12-06-2005, 09:51 PM | #8 | |
Join Date: Sep 2005
Location: Topeka, Kansas
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Re: Planet Destroyers
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Cleopatra: Whenever she assigned me to the switch, was that Voice, or was Raina influencing her thinking? Because, I mean, if it was Raina, she got inside my head and decided that I would screw it up. |
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12-06-2005, 10:14 PM | #9 | |
Join Date: Nov 2005
Location: Montreal, Canada.
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Re: Planet Destroyers
Okay, let's put some numbers into the problem:
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10 squares foot X 1" of Iron equal 1440 cubic inches. It got DR50 HT58. A cubic meter contain 64 000 cubic inches (40"X40"X40") 64 000/1440=44.4 sheets. So, a cubic meter of iron got DR2220 and HT2575 If we divide these numbers by two-thirds, we got the average stat of five tons of "Planet Earth"= DR1480 HT1716 from this, we can extrapolate the DR and HT of Earth: DR 1.77 x 1024 HT 3.08 x 1024 If the average draw on a six-dice face is 3.5, a weapon who will be able to destroy earth would need to be able to get this level of damage: 14D x 1023 Maybe i am wrong, but the maths tend to look that way. -EDIT- Just for the fun, in Gurps I.S.T. page 76 sidebar , they list a 10 Kiloton nuclear bomb at 8D x 106 flash damage and 12D x 106 concusion damage. If i remember well, Hiroshima was 14 Kilotons. Just to put things in perspective... Last edited by Toubrouk; 12-06-2005 at 10:27 PM. |
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12-06-2005, 10:27 PM | #10 | |
Join Date: Oct 2005
Location: Boston, MA
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Re: Planet Destroyers
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My math-fu isn't strong enough to appraise these figures, but here are some calculations regarding the power of the first Death Star, generated assuming that Aldaraan was roughly the same mass as the Earth. Bascially, he asserts that an Earthlike planet would require a minimum of 2.4*10^32 joules to destroy, and the energy imparted to the fragments whipping about after the planet was blown up raise the figure to an upper limit of 3.4*10^38. Interestingly enough, assuming that Yavin was roughly Jupiter-sized, he asserts that this enough energy to destroy Yavin, but not send the fragments whipping about at high velocity. So, the superlaser, according to his calculations, puts out at least 2.4*10^32 joules. I suppose one could convert this to dice, if so inclined, using the 3e Beam Weapon rules in Vehicles, but I think it would break the system. Does anyone want to hazard a guess at the joules to dice ratio in 4e? |
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