06-22-2013, 03:06 PM | #11 | |
Join Date: Nov 2008
Location: Yukon, OK
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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06-22-2013, 04:02 PM | #12 |
GURPS FAQ Keeper
Join Date: Mar 2006
Location: Kyïv, Ukraine
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
There's also the Establishment habitat unit (bar, brothel, casino, gym, massage parlour, nursery, salon, classroom, or retail store), which provides enough space for 20 patrons and 3 staff in the space of 2 cabins. Which is a total space of 5.32 to 16.64 hexes.
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06-22-2013, 04:03 PM | #13 |
GURPS FAQ Keeper
Join Date: Mar 2006
Location: Kyïv, Ukraine
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
I'm currently looking real hard at the idea of just calculating volume based on SM and dividing it by the systems involved. But I'm not sure which way to go: calculate the volume of a sphere of the same SM? (Spheres count as 2 SMs higher than their diameter would indicate.)
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06-22-2013, 04:25 PM | #14 | |
Join Date: May 2008
Location: CA
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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06-22-2013, 05:48 PM | #15 | |
Join Date: Jun 2013
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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EDIT: I wish I had my book with me, but it occurs to me that a rectangle with length/2=width is 1 SM larger than its height would indicate. A 2-yard-long, 1-yard-wide/high ship would be SM+1 under that ruling, while its face (a 1-yard square, so SM-2 +2 for being a square) would be SM 0. So, height/2=width may well be the rule for streamlined vessels, meaning unstreamlined will be closer to equal. A 1.5x1x1 yard vessel would be SM+0 from the side (SM-1, +1 for being "boxy") and SM+0 from the front (SM-2, +2 for being a square). So, it may be more accurate for unstreamlined to have (length*2/3)=height=width, while streamlined are (length/2)=height=width. Last edited by Varyon; 06-22-2013 at 06:01 PM. |
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06-22-2013, 05:59 PM | #16 | |
Join Date: Aug 2004
Location: In the UFO
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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From Kromm in answer to my question: > If so, what *is* the volume of a hex (not sure if the height is 1 or > 2 yards, also). Canonical hex height for powers and magic is in fact 12' (four yards), and has been since 1986; see pp. B101, B239 for the current references. Volume is thus ~93.53 cubic feet, or ~3.46 cubic yards. Thanks!
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06-22-2013, 06:04 PM | #17 | |
Join Date: May 2008
Location: CA
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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Also, the Pyramid Designers Notes apparently assume a density of less than 15 cubic feet per ton or more than 133 pounds per cubic foot; this is a ridiculously high density, making a Habitat more than twice as dense as water; it apparently assumes that a very large fraction of the habitat is solid metal. The density of armor is apparently on the order of 1,333 pounds per cubic foot, which is about three times as dense as steel. EDIT: This assumed a hex height of 2 yards for deckplan purposes; if it's supposed to be 4 yards, that's a ridiculously high deck and it'll halve the density figures I gave. |
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06-22-2013, 06:30 PM | #18 | |
Join Date: Jun 2013
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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Not that using density wouldn't work, of course, but I'm somewhat-unconvinced that we can decide on a semi-accurate density very easily. With what I'm proposing, an SM+8 unstreamlined vessel (30x20x20 yards) has a volume of around 12000 yd^3, while a streamlined one (30x15x15 yards) has a volume of around 6750 yd^3. This is going to make things a good deal more cramped on the SL vessel (assuming we have systems each take an ~equal chunk of space), which is as it should be (although these numbers may have a bit too much of a difference). An SM+8 sphere would have a volume of around 33000 yd^3, making it the roomiest option thus far. |
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06-22-2013, 07:13 PM | #19 | ||
Join Date: May 2008
Location: CA
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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I'm not sure why you're unconvinced about being able to get a semi-accurate density. It's not exactly all that difficult; we should be able to at least assume that the ship will at most be as dense as water (most likely less so); this is because ships are likely to be roughly as dense as sea ships, which have to be less dense than water in order to float. Even if we assume a density equal to water, we get a mass-volume multiplier of 32, yielding 32 cubic feet per ton. Thus, an SM+8 ship should have a volume of 32,000 cubic yards or higher. |
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06-22-2013, 07:43 PM | #20 | ||
Join Date: Jun 2013
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
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As for the SL vessel being twice the length of the US, I can't figure out any way to make that work. 2x length is going to correspond to +2 SM, meaning there needs to be an effective loss of -2 for targeting purposes. The only way to get this to work would be if a US is a square box/sphere while the SL is long enough that it doesn't get any + to SM from its width... but at the that point the SL vessel would be targeted at -2 from the front/back, rather than at the -1 given by SS. Looks like this may be one of those cases where the abstract nature of SS makes such an analysis break down... Quote:
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Tags |
deck plans, space, spaceships, volume |
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