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07-22-2024, 01:19 PM | #1 |
Join Date: May 2018
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Min ST penalties
Legacy ITL says that if you lack the ST required for a weapon (excepting crossbows):
If your ST is less than that required for the weapon you are using, your DX is -1 for each ST point you lack, and the damage done is -1 for each 2 ST (round damage down) that you lack. So how does the round down work? If you are 1 ST less, is damage at -1? If 3 ST less, is damage at -2 or -1? Now for Crossbows, damage is not changed, but the -1 DX penalty for every ST point lacking remains. |
07-22-2024, 02:30 PM | #2 |
Join Date: Aug 2004
Location: Pacheco, California
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Re: Min ST penalties
The final damage is rounded down towards negative infinity.
So lacking 3 ST is -2 damage and -3 DX. C.f. the Flinger article at TFT Companion page 15. Hopefully I'll make the Professional thief takes down Flinger video soonish.
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07-22-2024, 04:53 PM | #3 |
Join Date: Jun 2019
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Re: Min ST penalties
I beg to disagree with Henry. What is called for (in determining the damage penalty) is taking the number of ST points you are short (say 3) dividing it by 2 (resulting in 1.5), and rounding that result down (dropping the .5) resulting in this case for a penalty of 1.
A better way all such rules could be worded is to say "For every 2 whole entire points you are short (or ahead), apply a penalty (or bonus) of 1." Use of the word "round" can be ambiguous depending on sentence structure, but to say "for every 2 whole points" or "for every 3 whole points" is always clear.
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07-22-2024, 06:15 PM | #4 | |
Join Date: May 2018
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Re: Min ST penalties
Quote:
I agree that this rule could have been worded more precisely. Last edited by pzmcgwire; 07-23-2024 at 08:07 AM. |
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07-23-2024, 12:32 AM | #5 |
Join Date: Jun 2019
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Re: Min ST penalties
That is correct!
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