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#19 |
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Join Date: Aug 2004
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For the record, the means of determining how long it would take to get from one rotational period to another is:
A = 62.5 * [(P2 - P1)] / [P1 * P2 * M/D^5 * (S1 - S2)] A: time needed in billions of years P1: initial rotational period in hours P2: final rotational period in hours M: mass of planet in Earth masses D: diameter of planet in Earth diameters S1: sum of squares of tides from sun and satellites with orbital periods greater than P1 S2: sum of squares of tides from remaining satellites. For multiple satellites: First Step: P1 is randomly determined P2 is the longest satellite orbital period in hours (multiply days by 24) Subsequent Steps (skip to end if S2 >= S1): P1 is the previous step's P2 P2 is the next longest satellite orbital period in hours (multiply days by 24) repeat until you run out of satellites Last Step (skip if S2 >= S1): P1 is the previous step's P2 P2 is the planet's orbital period in hours (multiply years by 8766) For one satellite: First Step: P1 is randomly determined P2 is the satellite orbital period in hours (multiply days by 24) Last Step (skip if S2 >= S1): P1 is the previous step's P2 P2 is the planet's orbital period in hours (multiply years by 8766) For no satellites: P1 is randomly determined P2 is the planet's orbital period in hours (multiply years by 8766) Again, keep a running total of the A's; stop and interpolate the current rotational period if the running total equals or exceeds the system's age. (Oddly enough, the only equation I'm having trouble with is the interpolation of the current rotational period; and that's simple Algebra. Need sleep...) |
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| Tags |
| planets, space, system generation, tidal braking, tide, tide-locked, world generation |
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