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#11 | ||
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Join Date: Jun 2020
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#12 |
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Join Date: Feb 2005
Location: Berkeley, CA
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It depends on whether you're willing to use materials that we know actually exist and work as required, or if you're speculating wildly on materials. Carbon compounds can absolutely do a lot of things, but they aren't universally useful for all purposes -- for example, they tend to be brittle with nasty failure modes (and 2,000K sodium has a vapor pressure of 80 atmospheres...), and they simply aren't a replacement for metals in electrical applications. Also, even if your reactor core runs at 2,000K -- that probably means 1,000K radiators.
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#13 | |
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Join Date: Jun 2020
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However, with the RAW of THS's radiator construction rules, we're probably looking at a ratio of between 15.66kW:1sf and 32.3kW:1sf, depending on the tech level. |
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#14 |
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Join Date: Feb 2005
Location: Berkeley, CA
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In general the power emission is the black body constant (5.67e-8W/m^2/K^4) times area times temperature^4, so at 1,000K you get 56.7 kW/m^2 or 5.26 kW/ft^2. However, the total heat output of a reactor is generally somewhere around 2x the electrical power output, and the things you're using the power for also produce heat, so that's about 2 kW/sf, which is a reasonable TL 10 value, the TL 9 value is probably more like 1 kW/sf.
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#15 | ||
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Join Date: Jun 2020
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Quick question: What is a radiator's radiance when the temperature is 1200K, 1500K, or 2000K, respectively? Because that could explain a lot. |
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#16 |
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Join Date: Jan 2005
Location: Charlotte, North Caroline, United States of America, Earth?
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I believe this may be a useful source, though it's very, very dense. Our own Anthony Jackson is quoted quite frequently too, for what it's worth. Atomic Rockets. Winston suggests you design your radiator for 3/4s of the temperature of your heat source or do the scary maths.
Now, one cool thing is that at tl10, I think it's reasonable to assume room temperature super conductors. With those, you could create pretty powerful magnetic fields. If you then heat up an iron based solution to a certain point, it will lose it's magnetic properties and be expelled in a cloud into space. While in space, the iron dust will radiate away the heat really effectively, cooling enough to become magnetic and be caught in the magnetic field and recollected. You now have a really efficient radiator with a lot of extra neat things. Due to consisting of a diffuse cloud of iron dust in magnetic fields, it's rather resilient and rugged, so long as the magnets have power. A related idea is to use a magnetic field to contain some sort of plasma in a "bubble". In space, this could be used as a mag-sail, and would also make communication(and identification) with the ship quite difficult, if not nearly impossible, without shaping the magnetic field to provide some sort of window(which is likely possible) in the plasma bubble. In an atmosphere, this plasma bubble could be used as a sort of air foil and thermal barrier for the ship. In either case, the bubble will tend to swell to the limits of it's magnetic field, so it's inherently "adjustable", and it will tend to capture charged particles. Visually, I think this works out to ships having rather small "active" parts, and then the vast bulk of the ship being a sort of ephemeral latticework supporting magnetic fields for fusion rocket nozzles, plasma sails and radiators.
__________________
Hydration is key |
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#17 | |
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Join Date: Feb 2005
Location: Berkeley, CA
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THS is generally 'technically doesn't violate known physics but implausibly optimistic'. Last edited by Anthony; 12-06-2024 at 06:20 PM. |
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#18 | |
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Join Date: Jun 2020
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To be honest, some would say I'm ripping off Mass Effect radiator designs (though the idea of droplet radiators isn't Mass Effect; you know how the general populous perceives things). |
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#19 | |
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Join Date: Jun 2020
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So, using the equation you gave me, P = A * ε * σ * T^4, I'm assuming 0.85 in this example because Atomic Rockets says anything less than 0.8 is a horrible radiator. A= 32887.67616m^2 / 354000cf - based on THS's radiator area rules for a 708 Space septuplet (7) HePlaR rockets ε = 0.00000005670373 σ = 0.85 T = 1500K So, P = 32887.67616 * 0.00000005670373 * 0.85 * 1500^4, which goes to P = 32887.67616 * 0.00000005670373 * 0.85 * 5062500000000. If I did the math correctly, then P = 0.0018648539093040768 * 4303125000000, ending with P = 4,303,125,000,000 (or 4.303125 PW). ... and I feel like I messed up somewhere here. |
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#20 |
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Join Date: Feb 2005
Location: Berkeley, CA
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I'm not sure where "A = 32887.67616m^2 / 354000cf " comes from -- I'm pretty sure A is just 32887m^2. Other than that, 4,303,125,000,000 is 4.3TW, not 4.3PW.
I will, however, observe that HEPlaR is not a THS term, and TNE HEPlaR is superscience. |
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| Tags |
| gurps 3e, radiators, spaceships |
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