Quote:
Originally Posted by hcobb
Maximum length jump is at 45 degrees and reaches a quarter of the jump length in height. So rotate that vector and put all of jump into height instead.
For example, a one second duration maximum length jump is 5 m/s up and 5 m/s along the length and hence covers 5 m in that second. In the half second to reach maximum height you travel d = 0.5 * a * t^2 = .5 * 10 * (0.5)^2 = 1.25 meters in height (or a fourth the length as expected).
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But doesn't that assume that the same energy is going into a vertical jump as a horizontal jump? It seems to me that standing still and jumping straight up will have a lot less energy than running at 5m/second and jumping.