Another way to look at spin tethers (
GURPS Spaceships 7 p.22) involves its tensile strength and two ships of (possibly) unequal masses. Given that Mn and Gn are the respective mass (in tons) and gravities of ship "n" and T is the tensile strength of the tether in tons
load:
T/2 = G1*M1 = G2*M2
The mass of the tether would be T/20,000 tons (possibly adjusted by TL to reflect changes in materials), the cost $10*T and the
minimum length would be (G1+G2)*50 yards†. It may be longer and thinner and spin more slowly as long as the stress didn't exceed its tensile strength. Please note that
- mass and cost of this design feature only requires knowing the data for one ship,
- the external cradle should be installed on the larger ship,
- the center of spin would be Gn/(G1+G2) times the tether's total length from ship "n", and
- since it is carried as cargo in a hold or hangar bay, its mass can be ignored.
† GURPS Vehicles Expansion 1 from 3E recommends a minimum 100 yard/G spin radius (twice the 4E value) with three times that considered nominal. Also, the cost there was $10 per pound of total loaded mass, or $20K/ton.
Example: A 0.4 G spin tether for an SM+6 ship heading to Mars (local gravity .38 G) would have a tensile strength of 80 tons, cost $800 and mass 8 lbs. If attached to another SM+6 ship, its minimum length would be 40 yards (80 yards by 3E rules). If an SM+5 ship was attached, the g-force in the second ship would be 0.4*100/30=4/3 Gs and the minimum tether length would be 173 1/3 yards or 520 feet.
Dalton “who loves putting a new spin on things” Spence