|
|
|
|
|
#1 |
|
Join Date: Jul 2008
|
I'm not sure exactly what you're suggesting here, but it sounds very strange.
__________________
I don't know any 3e, so there is no chance that I am talking about 3e rules by accident. |
|
|
|
|
|
#2 | |
|
Join Date: Sep 2008
|
Quote:
In the example I gave, n = 100. So, if you have an ROF 500 gun, divide the ROF by 100 and get 5. Let's say this same gun has a recoil of 2. So, for every +2 you made the roll by, 5 bullets would hit, instead of 1. Change n to change flavor. 100 will give you mostly-realistic, and some might argue moreso, for truly insane RoF. If you change n to, say, 20, this makes it so that master marksmen can hit with nearly all the bullets of nearly any gun if they get critical successes. |
|
|
|
|
|
|
#3 | |
|
Wielder of Smart Pants
Join Date: Aug 2004
Location: Ventura CA
|
Quote:
Really, I don't see why you don't just have the mean number of shots hit. Take the percent chance of success (using the RoF bonus of a single gun) and multiply it by the number of shots. There's a complication there with PD, but I'm not sure that the PD rules aren't themselves deeply flawed. I guess you could throw in a randomizer that results in the expected number of hits within 1-2 standard deviations. Last edited by sir_pudding; 02-23-2012 at 03:25 PM. |
|
|
|
|
|
|
#4 |
|
Join Date: Nov 2009
Location: Oregon
|
What he's suggesting is that, for spaceships with RoF over 100, you multiply the Margin of Success by RoF/100 to determine number of hits. In other words, RoF 200 gives 2 hits per MoS/Rcl, RoF 300 gives 3 hits per MoS/Rcl, etc. If doing this, I'd also cap the Rapid Fire to-hit bonus at RoF 100. Otherwise, you'd have effective hit rate go up at RoF 200+.
|
|
|
|
|
|
#5 | |
|
Join Date: Sep 2008
|
Quote:
...or, y'know, not, for your Spaceships/Black Ops game. |
|
|
|
|
|
|
#6 | |
|
Join Date: Dec 2006
|
Quote:
So for example if you were firing with a RoF 200 and succeed by 5 (and your enemy failed to dodge)- you would normally hit with 5 shots, the remaining 195 going elsewhere. If you were going 'number of hits per MoS== RoF/100 min 1' then you would hit with 10 shots (200/100 = 2, MoS = 5, 5*2 = 10). I am not endorsing or decrying the approach, just clarifying. |
|
|
|
|
![]() |
| Tags |
| rof, spaceships |
|
|