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#11 |
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Join Date: May 2008
Location: CA
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For velocities close to c (such as 186,000 miles per second or 0.9985 c) you need to account for the relativistic mass's effect upon kinetic energy. You can do that by multiplying the damage by 1/(1-v^2/c^2)^(1/4) - that's the square root of the Lorentz factor (damage is proportional to the square root of kinetic energy while kinetic energy is directly proportional to mass). In this case, that means multiplying by 4.274.
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#12 | |
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GURPS FAQ Keeper
Join Date: Mar 2006
Location: Kyïv, Ukraine
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#13 | |
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Join Date: Aug 2004
Location: Louisville, Ky
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How long can a crew function at 1.5 G's? Minutes, hours? Specifically what accelerations are reasonable for combat maneuvering? And could a picked crew on a small ship push it a little higher? |
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#14 | |
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Join Date: Aug 2004
Location: Louisville, Ky
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Jeff |
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#15 | |
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Join Date: Feb 2005
Location: Berkeley, CA
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1G = 10,000N/ton, so power requirement = (mass in tons) * (velocity in m/s) * 10 kW. |
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#16 |
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Join Date: Aug 2004
Location: Louisville, Ky
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#17 |
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Join Date: Jan 2010
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It applies to both but reaction drives are dumping material out the back in order to do it rather than creating motion whole cloth from energy (though some reactionless engines create it from nothing).
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#18 |
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Join Date: Aug 2004
Location: Louisville, Ky
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Ah. I was not clear. I was envisioning 'reactionless' drives as using the hyperspace fluid as reaction mass. Essentially using hyperspace as an infinite capacity fuel tank.
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#19 | |
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Join Date: Jan 2010
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Lets say the tank holds 1kg or fluid and expels the whole contents at 2m/s every second. That's 2J of energy moving the ship forward but it also means your engine requires at least 2W in order to operate continuously (because those 2J per second have to come from somewhere). |
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#20 | ||
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Join Date: Aug 2004
Location: Louisville, Ky
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Quote:
Quote:
Maybe I'm tired, but I'm not seeing it. |
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| Tags |
| ftl, spaceships |
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