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#1 | |
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Join Date: Feb 2005
Location: Berkeley, CA
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Quote:
No, because your maximum speed is lower than your stall speed. Assume you need 0.1 Gs. |
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#2 | ||
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Join Date: Jan 2010
Location: Los Angeles County
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Quote:
Quote:
In this case I add 1/3 of a Jet Engine and 2/3 of a jet fuel tank to get 2 hours of ~.333 G acceleration in atmosphere. So now I need to know how long the Jet Engine is running during takeoff. I guess you find out how long it takes to get to max air-speed and turn the engine off after that. Okay: Time to max speed (in sec) = Max speed (in mph)/Acceleration (in mph/sec) Max speed (in mph) = 2,500 * SqRoot(Acceleration in Gs) Acceleration (in mph/sec) = Acceleration in Gs * 20 So in my case: Max speed (in mph) = 2,500 * SqRoot(.333) = 1443.38 Acceleration (in mph/sec) = .333 * 20 = 6.67 Time to max speed (in sec) = 1443.38/6.67 = 216.4 sec = 3.6 min = .06011 hours That's 33 trips to orbit! (I will still need 5.2 delta-V in Hydrogen for each trip) ^ does this look right? EDIT: I was ninja'd. :P So yeah .1 Gs seems about right. About Ram-Rockets, because air-speed is logarithmic adding the Ram-Rocket option to space drives if you already have .1+ Gs in atmo is not cost effective. But (not that I see this in the rules) don't ram-rockets need high air-speed to work in the first place? Why/how would you use a ram-rocket? Last edited by MatthewVilter; 10-29-2010 at 08:17 PM. |
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