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#1 |
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GURPS FAQ Keeper
Join Date: Mar 2006
Location: Kyïv, Ukraine
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Greetings, all!
I'm trying to estimate the time required for a spaceship to exit atmosphere. For reasons of tech available, exiting atmosphere is more important to me than attaining a stable Newtonian orbit. Thing is, unlike the usual Blast Off calculation, the time spent overcoming air and climbing is no longer negligible. So I'm trying to refine the calculations. Some of them seem straightforward, others less so. The simplest case seems to be a wingless high-thrust craft doing a vertical liftoff, in which case aerodynamic lift is effectively zero. At which point I can subtract local gravity from the drive's acceleration rating, and calculate top airspeed based on the remaining rating, calculate time required to accelerate and distance passed, then divide the remaining distance by top speed to get the approximate time taken. However, what happens in cases of a winged craft blasting off with an acceleration comparable to or less than the local gravity? Or an atmospheric craft climbing using wings and thrust in general? We can easily calculate horizontal top speed that can be achieved by a winged craft (at which it maintains enough aerodynamic lift to compensate against gravity), but the more one pulls one's nose up, the less efficient aerodynamic lift becomes, at some point resulting in a negative climbing rate if thrust is less than local gravity. So . . . how do I calculate that? Thanks in advance! |
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#2 |
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Join Date: Feb 2005
Location: Berkeley, CA
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A spaceship that is using wings to reach orbit does not permanently exit atmosphere until it reaches orbital velocity, or at least close enough that its thrust is able to make up for the difference, though it might make suborbital hops.
Climb rate for airbreathing engines is mostly about specific power. |
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#3 | |
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GURPS FAQ Keeper
Join Date: Mar 2006
Location: Kyïv, Ukraine
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Quote:
You mean the thrust-power-to-mass ratio? If so, assuming that a winged 'spaceship' has a thrust acceleration A (with A<G) and a top velocity V (with V>stall, obviously), how do I figure the climb rate? |
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#4 |
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Join Date: Feb 2005
Location: Berkeley, CA
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Raw climb rate isn't that relevant there -- the way you make a suborbital hop is by turning, and you don't actually need any thrust to make the hop (though you have to have somehow reached sufficient velocity, which requires thrust unless you're skipping as part of atmospheric skimming or re-entry).
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#5 | |
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GURPS FAQ Keeper
Join Date: Mar 2006
Location: Kyïv, Ukraine
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Quote:
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#6 | |
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Join Date: Feb 2005
Location: Berkeley, CA
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Quote:
I don't think this will really be much of a factor, it doesn't seem to require more than a few percent climb rate (particularly in comparison to other problems with how spaceships computes things, such as max atmospheric flight speed being totally wrong). |
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| Tags |
| blast off, spaceships, ssto, winged |
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