[Toubrouk]

Okay, let's put some numbers into the problem:

The Earth's mass is about 5.98 x 1024 kg.

The Earth has an average density of 5520 kg/m3 (water has a density of 1027 kg/m3). Earth is the densest planet in our Solar System.

http://www.enchantedlearning.com/sub...th/index.shtml

So, what we need to know is; what kind of explosive we need to blow a nice chunk of matter that got two-thirds the density of iron weighting 5.98 x 1024 kg.

10 squares foot X 1" of Iron equal 1440 cubic inches. It got DR50 HT58.
A cubic meter contain 64 000 cubic inches (40"X40"X40")

64 000/1440=44.4 sheets.

So, a cubic meter of iron got DR2220 and HT2575
If we divide these numbers by two-thirds, we got the average stat of five tons of "Planet Earth"= DR1480 HT1716

from this, we can extrapolate the DR and HT of Earth:

DR 1.77 x 1024
HT 3.08 x 1024

If the average draw on a six-dice face is 3.5, a weapon who will be able to destroy earth would need to be able to get this level of damage:

14D x 1023

Maybe i am wrong, but the maths tend to look that way.

-EDIT-

Just for the fun, in Gurps I.S.T. page 76 sidebar , they list a 10 Kiloton nuclear bomb at 8D x 106 flash damage and 12D x 106 concusion damage. If i remember well, Hiroshima was 14 Kilotons. Just to put things in perspective...