[Spaceships] Designers' Championship I: ground to LEO
Using the spaceship design rules in GURPS Spaceships, without superscience, what is the cheapest way to provide a shuttle service between the ground and low Earth orbit, at TL 9? At TL 10? At TL 11?
Ground rules:
What is the most cost-effective ground-to-orbit lighter you can build at each TL, without superscience? How are things different on a backwoods colony planet where there is only a liner in orbit 10% of the time, and where there is only one spaceport? |
Re: [Spaceships] Designers' Championship I: ground to LEO
By the way: is there any comment on the ground rules as set out?
How do wings affect Hnd? |
Re: [Spaceships] Designers' Championship I: ground to LEO
What about a space lift?
Is that super science? |
Re: [Spaceships] Designers' Championship I: ground to LEO
Space lifts are easily TL 9, given an adequately motivated and organized civilization.
A launch loop might be even cheaper than that, though. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
• Space lifts are no good for getting to LEO: you can't get off below GEO. And it takes a long time to get to GEO, which might make space lifts unattractive to passengers. Rotorvators, bolo space stations, and even space fountains sound more practical to me. • Space lifts eat up an awful lot of valuable territory in orbit, besides which they are mind-bogglingly capital-intense, and a very considerable engineering challenge. A beanstalk is equivalent to a suspension bridge with a 24,000-mile span. There might be a long wait before we get one built. We are much closer to building an orbital lighter. It is not clear to me that a space lift will ever be economic: operating costs are much lower than shuttles, but amortisation is through the roof, and there might be prohibitive rental costs on orbital territory. • Until we design the most cost-effective orbital lighter we don't know what price the space lift will have to compete with. I won't be surprised if at higher TLs lighters (perhaps fusion powered) provide a trip to LEO that is cheaper than a space lift ticket to GEO. • This design exercise will give us a basic approach to the more general problem of building lighters for trips from ground to low orbit on habitable planets. This will be important in the case of comparatively low-population colony worlds, which don't generate enough traffic to amortise a minimum-scale beanstalk. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Laser Launch system is the most cost effective(at low TLs), I believe, but that was in THS, not Spaceships.
Also, by highly radioactiv,e do you mean no orion drives, or no saltwater nuke drives? Orion drives are not that hazardous in terms of fall-out |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
I am, obviously, considering commercial operations: thousands of passengers per day. Regulators would be concerned with cumulative emissions over myriads of launches, plus of course the possible use of the bombs as bombs. Have you thought about Daedalus? |
Re: [Spaceships] Designers' Championship I: ground to LEO
The trouble with any sort of pulse system especialy the Daedalus fusion pulse system is the expense of the fuel, I don't currently own spaceships but I suspect that this will prove to be the killer for any sort of Orion/ Daedalus pulse engine in regular service. As the rules of the competion, if not the build system, appear preclude hybrid vehicles such as the Helios designs (two stage vehicles using a chemical first stage and a nuclear second stage) at least at TL 9, nuclear systems may not be all that credible for low tech levels.
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
The PDF is US$9.95, plus which printing and binding my copy cost me about US$4.90. I consider it to have been worth every penny. Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
The PDF is something I am going to get as of payday (the joys of being a student again- only so many hours a week you are physicaly able to work work etc). My coment about the Helios design (nominaly TL 7- at least when it was first proposed) being useless was not about staging but the emmisions problem, using the chemical stage to reach the stratosphere and then using a nuclear sustainer to finish the job seams to violate rule 1 quite thouroughly. Even a closed cycle engine is probably a dead end because of its low thrust, without TL 10+ fusion systems it isn't going to fly.
As of when I get a copy I will try runing up stats for one of the Helios RLV designs using TL 9 materials and components while it will almost certainly not be legal under the competition rules (or sane for that matter) it may provide a useful reference. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Don't mind sanity too much. I am a Girl Genius fan. My motto is "What would Baron Wulfenbach do?"
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Reaction Engine, Laser Rocket (TL 9) [REAR]
Laser rockets uses a ground based laser battery that evaporates reaction mass producing thrust. Each Laser Rocket engine must be powered by a laser battery, 10 GW for sm+5, 30 GW for sm +6, 100 GW for sm+7, 300 GW for sm+8 etc (the standard 1-3-10 progression). Each engine produces 2G of thrust, and each fuel tank of ablative plastic propellant gives 0,45mps of delta-V. Cost for the spaceship part of the engine is as a chemical rocket of same size, ablative plastic costs $200/ton. This is the Laser Launch Engine system as converted by Boobis, and numbers double checked by me. Mind if we use that? Main cost of launch is in the ground based power station, and a dedicated nuclear reactor should produce enough juice to send up a flight every five minutes. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Assume 10% per annum cost of capital (depreciation plus insurance plus interest), and that ground workers have average jobs. 1/6 down time for maintenance. The big issue might turn out to be getting enough traffic to keep the load factor up. Assume a 75% load factor, but keep an eye on passenger numbers: if you start pushing a billion passenger movements a year that might be a problem. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Well, you wire the plant into a local grid, any time traffic drops, you sell power output on the market for ground-based power
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Lasers. You build about 40,000 small ones, so you have exceptionally high reliability. Even if somehow, 5% of the lasers failed all at once, there would probably still be enough to get your payload in orbit, and you can do maintenance on the lasers without stopping launches. Plus, building one huge laser is much more expensive/technically difficult. And if you want to scale up your payload that you can launch, you just build more lasers.
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
I would normally calculate Return on Investment. So build cost may be only a small consideration. What ticket price can we charge? (what will the market bear?) |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Hmm, this seems like two different competitions. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
What is (at each TL) the shuttle that has the lowest ratio of total cost (ie. operating costs plus amortisation of investment) to the number of trips to orbit that it provides? Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
The essence is to establish what the price of a ticket to/from orbit is likely to be for a developed planet. |
Re: [Spaceships] Designers' Championship I: ground to LEO
I am guessing that a 6G laser launcher (5G effective) with 13 fuel tanks and 2 passenger seating will be the one to beat.
Is there a limit on the G force we can apply to passengers? Do we need to worry about the real G Force felt with nearly empty tanks? |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
I got as far as outline design for a laser launch vehicle before deciding that the base station cost is going to be very expensive. Even for a 4G size 5 craft you are looking at M$360+ for the base station. I now quite like the look of the Nuclear thermal rocket at TL9+. Though not sure if its exhaust is allowed? |
Re: [Spaceships] Designers' Championship I: ground to LEO
TL9+ Orbital Lighter (Spaceplane) v1 "Alida"
Alida class spaceplanes are cheap reusable single stage orbital lighters that can take off and land at a normal airport. Using a jet engine to take off it clears local population centres before going supersonic and accelerating to maximum air speed. It then engages the Nuclear Thermal rocket drive and climbs into orbit in under 7 minutes. Having docked and exchanged passengers it reenters atmosphere and then makes a slow descent back to Earth. On final approach it powers up its jet engine and lands at an airport. It can comfortably make the return journey once every two orbits or every 180 minutes. (It could probably make the journey every 1.5 orbits by constantly switching between landing sites in two hemispheres). Front 1 Armor (Advanced Laminate) 2-3 Passenger Seating (4 seats) 4-6 Fuel Tank (Hydrogen) 0 Control Room Central 1-6 Fuel Tank (Hydrogen) 0 Fuel Tank (1 hours Jet Fuel) Rear 1-5 Nuclear Thermal Rocket (2.5G) 6 Jet Engine (1G) dST/dHP 20, Hnd 4 atmo/0 space, SR 4/5, HT 12, Move 1G/2500 mph/0.69 mps, 2.5G/5.67 mps, LWt 30, Load 0.5, SM +5, Occ 1+4 SV, dDR 3, Cost M$ 1.44, TL9, Streamlined, Winged, Length 15 yards DeltaV 6.36mps (ample reserve) -Jet Engine 2500mph = 0.69mps -9 Hydrogen Fuel Tanks = 9*0.45*1.4 (9 tank adjustment) = 5.67 mps Draft economics: 1 flight every 3 hours operating for 7200 hours pa= 2400 flights per year 4 passenger seats at 75% loading = 3 passengers per trip = 7,200 passengers per year Variable cost per trip: Insurance = M$1.44/1000 = K$1.44 Servicing = M$1.44/100 = K$14.4 Fuel: 13.5 tons Hydrogen (K$27) + 1.5 tons Jet Fuel (K$6) = K$33 Total Variable = 1.44+14.4+33 = K$48.84 Annual Costs to Amortise: Requires 4 pilots at $7200 pm TL9 Comfortable salary each = K$345.6 pa Other economics = Insurance+Depreciation+RoI = 10% = K$ 144 Total Fixed = K$ 489.6 Divided over 2400 trips = $204 per trip Return Ticket price = K$49 / 3 passengers = $16,350 (4.5 months income for an average TL9 job) I don't see a significant difference between TLs other than the pilots wages increase, which adds about $30 per TL to the ticket price. On backwoods world you only employ one pilot part time so annual costs are K$34.56 + K$144 = K$178.56 / 240 trips = $744 per trip So ticket price per passenger increases by $250 to $16,600 on backwoods worlds As most of the ticket cost is variable cost the ticket price should scale with ship size fairly linearly. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
thtraveller |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
Just convert the Jet Engine to a NT Ram-rocket, lose the jet fuel tank, add a passenger seat module (+2 seats). Cost is now M$ 1.89. Return Ticket Price is now $10,640 (3 months basic income). Now has 3G drive to orbit, Top Air Speed 1800 mph (0.5 mps). |
Re: [Spaceships] Designers' Championship I: ground to LEO
TL9+ Orbital Lighter (Spaceplane) v2 "Alida"
Alida class spaceplanes are cheap reusable single stage orbital lighters that can take off and land at a normal airport anywhere in the world. Using a Nuclear Thermal Rocket in fuel-less air-ram mode to take off it clears local population centres before going supersonic and accelerating to maximum air speed in an easterly direction. It then engages the other normal Nuclear Thermal rockets and climbs into orbit in under 6 minutes. Having docked and exchanged passengers it re-enters atmosphere and then makes a rapid descent back to Earth. Again using its air-ram engine it lands at an airport. It can comfortably make the return journey once every two orbits or every 180 minutes. (It could probably make the journey every 1.5 orbits by constantly switching between landing sites in two hemispheres). Edit: The excess delta-V (6.17 mps versus the 4.6 mps required) allows for losses due to air-resistance and gravity. It also includes an emergency reserve (e.g. single engine failure in flight). The 3G thrust allows it to get it into orbit quickly to reduce gravitational losses. Edit: The excess delta-V also allows for the spaceplane to enter orbit from higher latitudes rather than on the equator (e.g. Europe) and hence not have the full benefit of 0.25 mps from equatorial spin. It also allows it to enter slightly higher orbits and also satisfies the G:Spaceships 5.6 mps orbital velocity requirement. Front 1 Armor (Advanced Laminate) 2-4 Passenger Seating (6 seats) 5-6 Fuel Tank (Hydrogen) 0 Control Room Central 1-0 Fuel Tank (Hydrogen) Rear 1-5 Nuclear Thermal Rocket (2.5G) 6 Nuclear Thermal Ram-Rocket (0.5G) dST/dHP 20, Hnd 4 atmo/0 space, SR 4/5, HT 12, Move Fly 0.5G/1800 mph/0.5 mps, Boost 3G/5.67 mps, LWt 30, Load 0.7, SM +5, Occ 1+6 SV, dDR 3, Cost M$ 1.89, TL9, Streamlined, Winged, Length 15 yards DeltaV 6.17mps (ample reserve) -Ram Rocket 1800mph = 0.5 mps -9 Hydrogen Fuel Tanks = 9*0.45*1.4 (9 tank adjustment) = 5.67 mps Economics: 1 flight every 3 hours operating for 7200 hours pa= 2400 flights per year 6 passenger seats at 75% loading = 4.5 passengers per trip = 10,800 passengers per year Variable cost per trip: Insurance = M$1.89/1000 = K$1.89 Servicing = M$1.89/100 = K$18.9 Fuel: 13.5 tons Hydrogen (K$27) Total Variable Cost = 1.89+18.9+27 = K$47.79 Annual Costs to Amortise: Requires 4 pilots at $7200 pm TL9 Comfortable salary each = K$345.6 pa Other economics = Insurance+Depreciation+RoI = 10% = K$ 189 Total Fixed Cost = K$ 534.6 Divided over 2400 trips = $223 per trip Return Ticket price = K$48 / 4.5 passengers = $10,640 (3 months income for an average TL9 job) I don't see a significant difference between TLs other than the pilots wages increase, which adds about $30 per TL to the ticket price. On a backwoods world you only employ one pilot part time so annual costs are K$34.56 + K$189 = K$223.56 / 240 trips = $932 per trip So ticket price per passenger increases by $210 to $10,850 on backwoods worlds As most of the ticket cost is variable cost the ticket price should scale with ship size fairly linearly. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Since cost mostly is from fuel, it might be cheaper to have more engines as ram-jets. You would be saving 0,58 mps worth of hydrogen each trip if you used three ram-jets, costing M2,4 extra. Also do you really need 3G's accel? Reducing to 1,5G gives you twice the amounts of passengers though I don't know what that will do with the timing-calculations from the ground-rules, but since T is k/A for some k (p. 37) we should be roughly doubling the to-orbit time, and I don't think 6 or 12 minutes will matter (but hey, I really don't understand much of the ground-rules). So shamelessly building upon your design I would do the Alida mk Boobis with three ram-jets and 6 passenger modules. Hoping that almost tripling the price of the shuttle and increasing to-orbit time with 6 min would pay of. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Note: I'm to lazy to do an actual complete design, but I'm tossing out ideas for grabs.
Quote:
Next is the cost of the pilot. While it's a small part you could employ a faux multistage design, doing an sm+5 upper stage without engines that never leaves the sm+6 lower stage. This lets you keep the sm+5 control-room but roughly six times your previous # passengers, giving you more seats/pilot (though I don't know what will happen with seats/shutle-cost). David stated in some post that this should really lower sr/hnd but that might be ok. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Well, you want at least 3G of accel to get out of earth orbit because 1G of that is going to be wasted negating earth gravity, so you can't really afford to drop engines, and, by the rules as written, ram-rockets are pretty expensive. It might make sense to allocate some tankage to water because it's cheaper, but water is going to come out a bit more radioactive, and might kill some of the dV, but it could allow for less engine because of the higher thrust.
Either way, using a standard, hydrogen-fueled jet engine, similar to the original design, allows the lighter to gain more altitude before it engages its fission thermal rockets, which might be more amenable to an eco-sensitive populace. I've been thinking, too, that it might make sense to use a laser-launch design that uses water as its primary reaction mass rather than ablative plastic. Water would be far less toxic, and is widely available. If, by RAW, water won't give enough isp to attain good dV while carrying enough passengers, hydrogen is probably a pretty good idea too. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
I think my economics might need revising slightly as the fission air ram is likely to need new fission cores every couple of years. Though ship cost isn't a major factor in the ticket price so likely only a few hundred dollars per ticket increase.
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Think of it this way - if you have a 1.5 G engine, you're only accelerating at .5G, but still burning 1.5 G of fuel. You can improve efficiency by angling your engine, giving you a maximum of 1G of vertical thrust to cancel out gravity and 1.12G of horizontal acceleration with 1.5 G thrusters, but your dV to LEO would be pretty compromised with only about 75% fuel efficiency... in other words, you'd need to burn about 30% more dV than your orbital velocity. With 3G of acceleration angled properly, you can have 2.83G of horizontal acceleration while canceling out gravity, for an efficiency of 94% - you'd only be burning about 6% more dV than your orbital velocity. Of course, considerations are a little more complicated because you still need to get out of atmo and you suffer from atmospheric drag, but those complications are greatly reduced with jets or ram-rockets to bring you to the top of the atmosphere.
As far as powering jets with hydrogen, a lot of scramjet designs burn H, and I imagine hydrogen will be a more common fuel in a hydrocarbon poor future than standard Jet-A. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
While it's neither in RAW nor ground-rules, it seems reasonable to somehow subtract (some factor of) planetary gravity at least when comparing launch-times. But 2G (3-1) is just four times higher than 0,5G (1,5-1) which should make a 1,5G thrust ship viable, shouldn't take more than 6x4=24 minutes, still not that high. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
This brings me to my conclusion. The ground-rules need updating. More precise rules for calculating fuel-consumption with/without wings, ram-jets and variable thrust. If there is a ~20-25% increase in fuel-efficiency if you increase thrust from 1,5G to 3G, as your numbers indicate, we need some way of actually calculating that. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Could someone take a look at this draft, for a TL 10 antimatter thermal lighter? All costs are in thousands:
Front 1 Armor (AML/SL) $60 dDR 3 2 Passenger (2) $10 3 Passenger (2) $10 4 Passenger (2) $10 5 Passenger (2) $10 6 Passenger (2) $10 0 Control Room $60 Central 1 AC Hydrogen Fuel $10 2 AC Hydrogen Fuel $10 3 AC Hydrogen Fuel $10 4 Armor (AML/SL) $60 dDR 3 5 Passenger (2) $10 6 Passenger (2) $10 0 Passenger (2) $10 Rear 1 ATR Ram-Rocket $750 2 ATR Ram-Rocket $750 3 ATR Ram-Rocket $750 4 ATR Ram-Rocket $750 5 ATR Ram-Rocket $750 6 ATR Ram-Rocket $750 Winged $150 Thrust 1.2 G SM 5 Air Speed 2739 mph dST/dHP 20 0.76 mps Hnd 4/0 Orbit DV 4.6 mps SR 5/4 Fuel DV 3.84 mps HT 12 Fuel Cost $16.67 $/mps TL 10 Fuel to Orbit $63.99 Loaded Wgt 30 tons Time to Orbit 10.35 Length 45 ft Cost $4,940 VC Per Trip Fixed Annual Op Ins $0.74 Ins $49.4 Service $0.45 Crew $537.6 Fuel $63.99 Dep+ROC $444.6 Total $65.18 Total $1,031.6 Flights/Year 2400 Passengers 12 /trip 28800 /year Total Costs $157,468 Cost/Passenger $5.47 |
Re: [Spaceships] Designers' Championship I: ground to LEO
<deleted>
I'm sorry, that was uncalled-for. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Well, if you really want to mess with things, I'm sure we can integrate over the path of the rocket, factoring in losses due to gravity at a given height, losses due to atmospheric drag dependent on speed, latitude, and altitude, and variations depending on the latitude and direction of launch. It would be a good exercise in whether or not I can still calculate an integral that complex, but, we can probably just forget about atmospheric drag if pretty much every design uses a ram-rocket or jet component, and estimating losses due to gravity for LEO insertion is pretty simple too.
I've had another thought too - I'm not sure if it's occurred to anybody to take passenger comfort into account - most people don't appreciate being accelerated at rates approaching 3G for an extended period of time. For example, you don't want to have to resuscitate Grandma on her way to visit her son who's working in Luna-3 Colony. It might be that a slower, though lossier lighter is preferable to a faster one. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
The exhaust during boost is very radioactive. ;-) The component and total ship costs all look fine. Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Heh, taking a strict interpretation of the ground rules allows me to build a shuttle with a single 0.5 Fusion Thermal Ram Rocket (0.5 mps dV), 8 fuel tanks (4.32 mps dV), 2 armor, 1 control room, 8 passenger modules (16 seats). This would reduce the return ticket costs per passenger down to $3,150 each. ;-)
Anyway back to "reality". Note my original design (with 6.17 mps dV) allowed for losses due to air-resistance and gravity (though not a full 1G loss as it is winged) and included a reasonable emergency reserve (e.g. single engine failure in flight). The 3G thrust was to get it into orbit quickly to reduce gravitational losses. I also thought the excess delta-V would allow for the spaceplane to enter orbit from higher latitudes rather than on the equator (e.g. Europe) and hence not have the full benefit of 0.25 mps from equatorial spin. Or enter slightly higher orbits and also satisfy the G:Spaceships 5.6 mps orbital velocity requirement. I will add that to the color text. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Note: I still claim no knowledge in this.
I can't get this out of my head. I get the fact that delta-V is delta-V and that the amount of delta-V required is constant regardless of acceleration. But it seems to me that the amount of fuel needed to attain a certain amount of delta-V might not be independent of your acceleration. Using my high-school physics, and an idealized (silly?) model disregarding wings, rotation, rocket equations and angles I get the (quite possibly flawed) numbers: Unit-engine: 10 kgm/s^2 thrust using 1 l/s of fuel Ship-mass: 1 kg in total, regardless of engines and fuel left Fuel: 100 l Hell, thats some darn light fuel :) Installing 2 unit-engines in the ship gives me 1 G of net acceleration for 50 seconds, amounting to 500 m/s delta-V. Installing 4 unit-engines gives me 3 G of net acceleration for 25 seconds amounting to 750 m/s of delta-V. Now elustran claims Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Where does the energy go? A rocket ends up with the same potential energy, regardless of 3G or 1.1G acceleration if it finishes in the same orbit. However, flying straight up at either thrust won't end you in a stable orbit, so this isn't necessarily straightforward. GURPS Spaceships doesn't take any fuel-efficiency variations into account. Why not? That said, its a role-playing system designed for people who probably don't like integrals. Its probably simplified. It sounds like it probably doesn't matter too much for the purposes of the contest. Which isn't the same as me claiming vindication. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
1) goto to http://www.orbitersim.com download orbiter and launch some rockets to get a feel how it works.
2) Your orbit is the result of a vertical vector and a horizontal vector. At burnout you want your vertical vector to be ZERO and your horizontal vector to be orbital velocity. Your orbital velocity is dependent on high your orbit is. The problem is that you need to go vertically to that high in the first place. But at the end you need to be going horizontally. If you have unlimited fuel you could go up to the desired height, start thrusting horizontal thrust while maintaining enough vertical thrust so you don't fall until you reach orbital velocity. If you don't then that where trajectory analysis comes in. Your trajectory will start straight up and gradually pitch down until you are horizontal at some point. The idea is to gain height and horizontal velocity while minimizing the loss of velocity in your vertical component due to gravity. Basically the first part of your trajectory is design to gain enough vertical velocity so that the second half of your trajectory can be designed to gain horizontal velocity. At the end of your trajectory your vertical velocity will be zero. This all assume you are trying to reach a circular orbit. Other types of orbits have their own target altitude, horizontal, and vertical velocity. But the idea is the same. At the end of the trajectory your are the right height, with the right combination of horizontal and vertical velocity. Last for Earth and other inhabitable planets, you have to account for drag induced by the atmosphere. Of particular important is dynamic pressures. There is a point, called MaxQ, where dynamic pressure is at a maximum during ascent. It can be great enough to tear your vessel apart. So a trajectory has to be designed to account for both atmospheric drag and keeping MaxQ within the vessel's structural limit. Both atmospheric drag and gravity's pull on your vertical velocity are the reason why you want to have a high thrust in trying to get into orbit. The more time you spending getting up to speed the more time both drag and gravity have to bleed off your speed. This will raise the amount of delta-vee needed to get into orbit. Finally for game purpose all of this can be abstracted away by a simple delta-vee formula. You will need slightly more delta-vee for a world with an atmosphere. If you want to get more complex you could factor in the thrust time. In this case the higher a planet's gravity the worse the effect on a low thrust engine. But I think the current rules are good enough for the purpose. While I am not from NASA or the aerospace industry. I spent a number of years developing add-ons for orbiter that accurate replicate the performance and controls of the Mercury and Gemini space capsule. This included the rockets they rode on (Redstone, Atlas-D, Titan 2). Orbiter has a text configuration option for spacecraft. you can go in and change the parameters to whatever design you come up with. Fly it on the trajectory you will think works and find out what really happens. Enjoy Rob Conley http://www.ibilbio.org |
Re: [Spaceships] Designers' Championship I: ground to LEO
Thanks for taking a look!
Quote:
Quote:
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
That should make your design pretty cost effective. Quote:
Why x10 for handling? It is winged so handling is 4. Did I miss some more small print? |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
According to Chansith's formula I calculate
1.2G is 55% fuel efficient (8.3 mps dV required) 1.5G is 75% (6.2) 2.0G is 87% (5.3) 2.5G is 92% (5.0) 3.0G is 94% (4.9) So I could drop the thrust (and engines) of the Alida to 2G to make it only 87% efficient as long as I have at least 5.3 mps of deltaV (which I already do). It works out much more economical as I get another 3 passengers to share the cost. |
Re: [Spaceships] Designers' Championship I: ground to LEO
TL9+ Orbital Lighter (Spaceplane) v3 "Alida"
Alida class space planes are cheap reusable single stage orbital lighters that can take off and land at a normal airport anywhere in the world. The relatively low 2G drive allows for a reasonably comfortable passenger experience. It can easily make the return journey to and from orbit once for every two orbits of the space station or every 180 minutes. Using Nuclear Thermal Rockets in fuel-less air-ram mode to take off it clears local population centres before going supersonic and accelerating to maximum air speed in an easterly direction. It then engages the other normal Nuclear Thermal rockets and climbs into orbit in seven minutes. Having docked and exchanged passengers it re-enters atmosphere and then makes a rapid descent back to Earth. Again using its air-ram engines it lands at an airport. Its reserve delta-V allows for the Alida to enter orbit from higher latitudes rather than on the equator (e.g. Europe) and hence not have the full benefit of 0.25 mps from equatorial spin. It also allows it to enter orbit even if one of the engines fails during boost. Normally it enters orbit with at least two tons of hydrogen remaining which it can sell in orbit at a profit. Front 1 Armor (Advanced Laminate) 2-6 Passenger Seating (10 seats) 0 Control Room Central 1-0 Fuel Tank (Hydrogen) Rear 1-2 Fuel Tank (Hydrogen) 3-4 Nuclear Thermal Rocket (1.0G) 5-6 Nuclear Thermal Ram-Rocket (1.0G) dST/dHP 20, Hnd 4 atmo/0 space, SR 4/5, HT 12, Move Flight 1G/2500 mph/0.69 mps, Move Boost 2G/5.67 mps, LWt 30, Load 1.1, SM +5, Occ 1+10 SV, dDR 3, Cost M$ 2.21, TL9, Streamlined, Winged, Length 15 yards DeltaV 6.36 mps (1+ mps reserve) -Ram Rocket 2500mph = 0.69 mps -9 Hydrogen Fuel Tanks = 9*0.45*1.4 (9 tank adjustment) = 5.67 mps Note losses due to gravity drag of the 2G drive means that the boost phase is only 87% efficient in fuel usage, and so requires a total of 5.2 mps delta-V to reach orbit ([4.6-0.69]/0.87 + 0.69). The fuel reserve of over 1 mps allows the Alida to make orbit even if one of its four engines fail (and efficiency drops to 75%). Economics: 1 flight every 3 hours operating for 7200 hours pa= 2400 flights per year 10 passenger seats at 75% loading = 7.5 passengers per trip = 18,000 passengers per year Variable cost per trip: Insurance = M$2.21 * 0.001% = $22 Servicing = M$2.04 * 0.01% = $204 Fuel: 13.5 tons Hydrogen (K$27) Total Variable Cost = K$ 27.226 Annual Costs to Amortise: Requires 4 pilots at $7200 pm TL9 Comfortable salary each = K$345.6 pa Other economics = Insurance + Depreciation + RoI = 10% = K$ 221 Total Fixed Cost = K$ 566.6 Divided over 2400 trips = $236 per trip Return Ticket price = K$27.5 / 7.5 passengers = $3,700 (1 months income for an average TL9 job) Note this price assumes the excess hydrogen fuel is wasted and not sold on or reused. So there is scope to reduce the price further to around $3000 per passenger. There is no significant difference between TLs. The pilots wages do increase per TL, but this only adds about $30 per TL to the ticket price. On a backwoods world with only 10% of the demand you only employ one pilot part time so annual costs are K$34.56 + K$221 = K$256 / 240 trips = $1065 per trip So ticket price per passenger increases by $142 to $3,850 on backwoods worlds The ticket price should stay approximately the same as ship size increases. |
Re: [Spaceships] Designers' Championship I: ground to LEO
That looks good. Why just two ram-rockets out of 4?
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Though you have a good point, extra fuel-less delta-V saves Hydrogen fuel on every flight. The extra 0.28mps pre boost would save 0.76 tons of fuel per trip or $1520 * 2400 trips = K$3600 per year. Wow. Yup, it needs 4 ram-rockets. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
I am looking for a way to use water as reaction mass, because then I can go down to 1 passenger per trip and it is still more economical. As long as I can fit the drives and fuel in 17 spaces it is doable. Hmm, 15 fuel tanks (water) plus 2 water NTR ram-rockets is tantalisingly close to doable. ... I have an idea about burning some fuel to get air speed rather than orbit, but I need to do the math. How long does it take to get air speed from 2500 mph to 4300 mph at 3G? I think it is 30 seconds, which is almost 4 tanks of fuel. |
Re: [Spaceships] Designers' Championship I: ground to LEO
OK I can't make it work with just water, yet... But I can make it work with one water NTR and one hydrogen NTR, a quarter of the fuel is hydrogen.
Edit: Not sure if that helps the ticket price much. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Using two different drives: half water, half hydrogen I reduced the return ticket price to low-earth-orbit to $2,400.
If we can work out how to do an all water drive the ticket price should drop to about half this. TL9+ Orbital Lighter (Spaceplane) v5 "Alida" Alida class space planes are cheap reusable single stage orbital lighters that can take off and land at a normal airport anywhere in the world. The relatively low 2G drive allows for a reasonably comfortable passenger experience. It can easily make the return journey to and from orbit once for every two orbits of the space station or every 180 minutes. Using Nuclear Thermal Rockets in fuel-less air-ram mode to take off it clears local population centres before going supersonic and accelerating to maximum air speed in an easterly direction. It then boosts into orbit in less than seven minutes. Having docked and exchanged passengers it re-enters atmosphere and then makes a rapid descent back to Earth. Again using its air-ram engines it lands at an airport. A novelty of the design is it uses two different fuels to reach orbit in order to reduce both the craft price and running costs. Half of its fuel delta-V comes from Hydrogen and half from Water. Front 1 Armor (Advanced Laminate) 2-3 Passenger Seating (6 seats) 5-6 Fuel Tank (Water) 0 Control Room Central 1-0 Fuel Tank (Water) Rear 1 Fuel Tank (0.75 Water, 0.25 Hydrogen) 2-4 Fuel Tank (Hydrogen) 5 Nuclear Thermal Ram-Rocket (Hydrogen 0.5G) 6 Nuclear Thermal Ram-Rocket (Water 1.5G) dST/dHP 20, Hnd 4 atmo/0 space, SR 4/5, HT 12, Move Flight 1G/2500 mph/0.69 mps, Move Boost 2G/4.68 mps, LWt 30, Load 0.7, SM +5, Occ 1+6 SV, dDR 3, Cost M$ 1.93, TL9, Streamlined, Winged, Length 15 yards DeltaV 5.37 mps (0.17 mps reserve) -Ram Rocket 2500mph = 0.69 mps -9.75 Water Fuel Tanks 9.75*.15*1.6 (13 tank adjustment) = 2.34 mps -3.25 Hydrogen Fuel Tanks = 3.25*0.45*1.6 (13 tank adjustment) = 2.34 mps Note losses due to gravity drag of a 2G drive means that the boost phase is only 87% efficient in fuel usage, and so requires a total of 5.2 mps delta-V to reach orbit ([4.6-0.69]/0.87 + 0.69). Economics: 1 flight every 3 hours operating for 7200 hours pa= 2400 flights per year 6 passenger seats at 75% loading = 4.5 passengers per trip = 10,800 passengers per year Variable cost per trip: Insurance = M$1.93 * 0.001% = $19 Servicing = M$1.78 * 0.01% = $178 Fuel: 4.875 tons Hydrogen = $9,750 Fuel: 10.75 tons Water = $293 Total Variable Cost = $ 10,240 Annual Costs to Amortise: Requires 4 pilots at $7200 pm TL9 Comfortable salary each = K$228 pa Other economics = Insurance + Depreciation + RoI = 10% = K$ 193 Total Fixed Cost = K$ 538.6 Divided over 2400 trips = $224 per trip Return Ticket price = $10,465 / 4.5 passengers = $2,325 (less than 3 weeks income for an average TL9 job) There is no significant difference between TLs. The pilots wages increase per TL, which adds only about $30 per TL to the ticket price. On a backwoods world with only 10% of the demand you only employ one pilot part time so annual costs are K$34.56 + K$193 = K$376 / 240 trips = $950 per trip. So ticket price per passenger increases by $210 to $2,535 on backwoods worlds The ticket price should stay approximately the same as ship size increases. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Actually, that isn't terribly unrealistic: air has an average molecular weight of about 29, and therefore really ought to give you 3.8 times the thrust of hydogen. It isn't RAW or groundrules, but realistically a winged design with four NTR ram-rockets can get up to about 2 miles per second without using any fuel at all. (Thrust is nearly 8 gee, but balanced by air resistance: it won't squash the passengers). Six tanks of hydrogen will get you up to 4.7 miles per second, plus 0.25 from rotation gets you into orbit. The craft is a bit pricey, but allows 14 spaces of passenger seating. |
Re: [Spaceships] Designers' Championship I: ground to LEO
I like the progressive refinement that's been done to the Alida craft. Maybe we'll meet in orbit 20 years hence after riding a very similar spacecraft. However, I've had a few thoughts regarding the design. If you want to save the eye-strain, the first three are annoying commentary. The last one is potentially useful.
1) From what I've read, it seems that the biggest issue doesn't come from radioactive exhaust (unless you directly pass air into the reactor instead of using exchangers) but directly from the reactor itself. Reactors would tend to require a lot of shielding to protect pilots, which is why some historical nuclear aircraft (ram or otherwise) were unmanned concepts. All that being said, it's possible that a TL9 reactor could be build efficiently enough that radioactivity and required shielding is minimized. 2) Now, another issue that needs to be contended with in a nuclear aircraft is the potential for failure. Would the aircraft have failure modes to ensure that the nuclear reactors wouldn't pose a threat of contamination? It's possible to launch the aircraft over oceans, but there is always the possibility of the aircraft failing over land and the possibility that failure over an ocean could still lead to radioactivity being carried to a population center through ocean currents or causing problems with marine life. Again, here's a situation we could handwave away by saying that a TL9 reactor would be using safer power generation methods, maybe some variant of a pebble-bed, which would also help with refueling, but failure is still a potential problem. If a nuclear lighter such as this design is ever proposed, expect anti-nuke protests. 3) Nuclear issues aside, I've had a couple of other thoughts specifically about the design. One issue is that the water rocket will burn out faster than the hydrogen rocket - they both provide the same amount of dV, but the water rocket produces 3x the thrust and will therefore burn out 3x as fast. You could assume that the pilot varies the level of water being fired in order to maximize ascent characteristics, or you could even assume that both rockets are capable of firing hydrogen or water and able to vary the mix since they are already capable of variable fluid-flow due to being ram-rockets. Of course, I'm not sure what the overall effect would be on your dV requirements, making this paragraph more of a nuisance than anything else... 4) Now the only thought of mine that you can actually easily apply to the craft is to assume that the craft doesn't have a physical pilot. Alida could potentially be flown by computer, especially since the flight path would be set before-hand. This would allow for one more passenger seat where the controls used to be and eliminate the expense of a pilot, though it would add the expense of better computing and AI flight software. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
If I could get the average per engine air-thrust to 1G for each of two engines then an all water design is doable. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
Quote:
Quote:
Fission air-rams are a no-global-warming alternative for jet engines too. So if we can make them relatively safe then we can save all our flight carbon emissions. Quote:
Quote:
Or AI pilot with remote living pilot on standby (remotely piloted space shuttle). Actually I can make an all water craft work (with 0.66 mps excess) if I just have one passenger in the pilot seat (16 tank, 2 drive, armor, controls). The return ticket price for that one passenger (actually 0.75 passenger by the ground rules) would be only $1200 assuming I have to pay the AI pilot (or $1000 if I don't). |
Re: [Spaceships] Designers' Championship I: ground to LEO
Edit: updated for two orbiters, associated economics, and extra color text.
I found a way to use an all water design and get the ticket price below 1 weeks wages... TL9+ Orbital Lighter (Lifter and Spaceplane) v6 "Alida" Alida class space planes are cheap reusable two part orbital lighters that can take off and land at a normal landing strip anywhere in the world that has a clean water supply. It can easily make the return journey to and from orbit once for every two orbits of the space station or every 180 minutes. The lifter craft and the orbiter craft are both capable of independent operation and flight. The orbiter rides under the lifter until separation above the atmosphere. Both use easy to obtain water as their reaction mass. Using Nuclear Thermal Rockets in fuel-less air-ram mode the lifter takes off and clears local population centers before going supersonic and accelerating to maximum air speed in an easterly direction. It then boosts towards orbit until it runs out of reaction mass. At this point the orbiter detaches and engages its rockets and completes the climb into orbit. The lifter drops back into atmosphere and flies back to its base using its engines in air-ram mode. Having docked and exchanged passengers the orbiter re-enters atmosphere and then makes a rapid descent back to Earth. Again using its air-ram engines it lands on its airstrip about an hour after it took off. There it picks up a second Alida orbiter and makes the trip again half an hour later. The Lifter therefore cycles every 90 minutes and each orbiter every 180 minutes. Typically these craft take off over water and international airspace as few countries want fission craft flying over their territory. So, they typically take off from equatorial coastal countries and islands with several hundred miles of water to their east. Alida Lifter “Big Al”: Front 1-6 Upper Stage (Orbiter) Central 1 Armor (Metallic Laminate) 2-6 Fuel Tank (Water) 0 Control Room Rear 1-2 Nuclear Thermal Ram-Rocket (Water 3G) 3-0 Fuel Tank (Water) dST/dHP 30, Hnd 4 atmo/0 space, SR 5/4, HT 12, Move Flight 1G/2500 mph/0.69 mps, Move Boost 3G/2.1 mps, LWt 100, Load 0.1, SM +6, Occ 2+0 SV, dDR 3, Cost M$ 6.1, TL9, Streamlined, Winged, Length 40 yards DeltaV 2.79 mps (effective 2.67 mps after gravity drag) -Ram Rocket 2500mph = 0.69 mps -10 Water Fuel Tanks 10*0.15*1.4 (10 tank adjustment) = 2.1 mps Alida Orbiters “Little One” and “Little Two”: Front 1 Armor (Metallic Laminate) 2-0 Passenger Seating (12 seats) Central 1-6 Fuel Tank (Water) 0 Control Room Rear 1-4 Fuel Tank (Water) 5-6 Nuclear Thermal Ram-Rocket (Water 3G) dST/dHP 20, Hnd 4 atmo/0 space, SR 5/4, HT 12, Move Flight 1G/2500 mph/0.69 mps, Move Boost 3G/2.1 mps, LWt 30, Load 1.3, SM +5, Occ 1+12 SV, dDR 2, Cost M$ 1.9, TL9, Streamlined, Winged, Length 20 yards DeltaV 2.1 mps (effective 1.98 mps after gravity drag) -10 Water Fuel Tanks 10*0.15*1.4 (10 tank adjustment) = 2.1 mps Combined Effective Delta-V of Lifter and Spaceplane = 2.67 + 1.98 = 4.65 mps Economics: 1 flight every 3 hours operating for 7200 hours pa= 2400 flights per year 12 passenger seats at 75% loading = 9 passengers per trip = 21,600 passengers per year per orbiter = 43,200 for two orbiters Variable cost per orbiter trip (includes use of lifter): Insurance = M$8.0 * 0.001% = $99 Servicing = M$6.9* 0.01% = $690 Fuel: 65 tons Water (50+15) = $1300 Total Variable Cost = $ 2,089 Annual Costs to Amortise from two orbiters and one lifter: Requires 12 pilots at $7200 pm TL9 Comfortable salary each = K$1,037 pa Other economics = Insurance + Depreciation + RoI = 10% = K$990 Total Fixed Cost = K$ 2,027 Divided over 4800 trips = $423 per trip Return Ticket price = $(2089+423) / 9 passengers = $279 (less than 1 weeks net income for an average TL9 job) There is no significant difference between TLs. The pilots wages increase per TL, which adds only about $10 per TL to the ticket price. On a backwoods world with only 10% of the demand you only employ two pilots part time and only have one orbiter so annual costs are K$70 + K$800 = K$870 / 480 trips = $1813 per trip. So ticket price per passenger increases to $434 on backwoods worlds The ticket price should stay approximately the same as ship size increases if you want to scale up to bigger craft and more passengers per trip. |
Re: [Spaceships] Designers' Championship I: ground to LEO
Excellent! Can you use one lifter to juggle two or even three orbiters?
|
Re: [Spaceships] Designers' Championship I: ground to LEO
Quote:
|
| All times are GMT -6. The time now is 04:38 AM. |
Powered by vBulletin® Version 3.8.9
Copyright ©2000 - 2024, vBulletin Solutions, Inc.