Spaceships, Floor / Deck Plans, Volume and Hexes
Greetings, all!
Trying to figure out the amount of space, I see something troubling. According to the author's expansion, an SM+8 ship's systems provide about 16-50 one-yard hexes each. A Habitat module for SM+8 provides 6 Cabins, with each cabin being suitable for accommodating two people. That's somewhere between 1.33 to 4.16 hexes per person. A single one-yard hex is the equivalent of 0.54m² (0.64yd²). At best, this means 2.24m² (2.66yd²) of place per person. How is one supposed to fit a bed, let alone a cabin, into that amount of space? Thanks in advance! |
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
A bed is only about 1 yard by 2 yards; it should fit within 2 hexes.
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And if a bed is 1 yard by 2 yards, that makes it 2 square yards. A hex is 0.64yd², so it takes 3.125 hexes for the bed alone. I wonder if calculating volume from SM is actually a better idea. |
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Second, yes a bed will extend a *little* bit into the corners of the 'edge' hexes, but it's close enough. Third, beds are still likely to be bunk-beds even in Cabins. |
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Yup, when I ran a hard-SF space campaign, most astronauts got a coffin which was their room, entertainment, personal storage and bunk, all-in-one. Since everything was in zero-g, habitat sections resembled hives, with bunks on every wall.
Y'know, like this. |
Re: Spaceships, Floor / Deck Plans, Volume and Hexes
Imagine an hexagon, now name the edges A, B, C, D, E and F.
If 1y is from the edge A to edge D, then it is 0.64952y², rounded to 0.65y² If 1y is from line AB to line DE, then it is 0.866y² Thats a 4/3 difference. |
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Er, the edge length of a GURPS hex isn't half a yard. The edge length is about 0.58 yards.
A GURPS hexagon has a side-to-side length of 1 yard (so to travel through one whole hex you travel one yard). Call this side-to-side length 'd'. The area of a hexagon is sqrt(3)/2 * d^2, or in this case just sqrt(3)/2, or 0.866. Quote:
A GURPS hexagon has a distance of 1 yard from line AB to line DE - that's the distance someone would need to travel to cross the hexagon from a hex directly below it to the hex directly above it. The distance from one vertice of the hex to the opposite one doesn't matter at all; it's not something that's within the GURPS definition of the hex and has no relation whatsoever to hex-based movement. |
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There's also the Establishment habitat unit (bar, brothel, casino, gym, massage parlour, nursery, salon, classroom, or retail store), which provides enough space for 20 patrons and 3 staff in the space of 2 cabins. Which is a total space of 5.32 to 16.64 hexes.
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Re: Spaceships, Floor / Deck Plans, Volume and Hexes
I'm currently looking real hard at the idea of just calculating volume based on SM and dividing it by the systems involved. But I'm not sure which way to go: calculate the volume of a sphere of the same SM? (Spheres count as 2 SMs higher than their diameter would indicate.)
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EDIT: I wish I had my book with me, but it occurs to me that a rectangle with length/2=width is 1 SM larger than its height would indicate. A 2-yard-long, 1-yard-wide/high ship would be SM+1 under that ruling, while its face (a 1-yard square, so SM-2 +2 for being a square) would be SM 0. So, height/2=width may well be the rule for streamlined vessels, meaning unstreamlined will be closer to equal. A 1.5x1x1 yard vessel would be SM+0 from the side (SM-1, +1 for being "boxy") and SM+0 from the front (SM-2, +2 for being a square). So, it may be more accurate for unstreamlined to have (length*2/3)=height=width, while streamlined are (length/2)=height=width. |
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From Kromm in answer to my question: > If so, what *is* the volume of a hex (not sure if the height is 1 or > 2 yards, also). Canonical hex height for powers and magic is in fact 12' (four yards), and has been since 1986; see pp. B101, B239 for the current references. Volume is thus ~93.53 cubic feet, or ~3.46 cubic yards. Thanks! |
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Also, the Pyramid Designers Notes apparently assume a density of less than 15 cubic feet per ton or more than 133 pounds per cubic foot; this is a ridiculously high density, making a Habitat more than twice as dense as water; it apparently assumes that a very large fraction of the habitat is solid metal. The density of armor is apparently on the order of 1,333 pounds per cubic foot, which is about three times as dense as steel. EDIT: This assumed a hex height of 2 yards for deckplan purposes; if it's supposed to be 4 yards, that's a ridiculously high deck and it'll halve the density figures I gave. |
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Not that using density wouldn't work, of course, but I'm somewhat-unconvinced that we can decide on a semi-accurate density very easily. With what I'm proposing, an SM+8 unstreamlined vessel (30x20x20 yards) has a volume of around 12000 yd^3, while a streamlined one (30x15x15 yards) has a volume of around 6750 yd^3. This is going to make things a good deal more cramped on the SL vessel (assuming we have systems each take an ~equal chunk of space), which is as it should be (although these numbers may have a bit too much of a difference). An SM+8 sphere would have a volume of around 33000 yd^3, making it the roomiest option thus far. |
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I'm not sure why you're unconvinced about being able to get a semi-accurate density. It's not exactly all that difficult; we should be able to at least assume that the ship will at most be as dense as water (most likely less so); this is because ships are likely to be roughly as dense as sea ships, which have to be less dense than water in order to float. Even if we assume a density equal to water, we get a mass-volume multiplier of 32, yielding 32 cubic feet per ton. Thus, an SM+8 ship should have a volume of 32,000 cubic yards or higher. |
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As for the SL vessel being twice the length of the US, I can't figure out any way to make that work. 2x length is going to correspond to +2 SM, meaning there needs to be an effective loss of -2 for targeting purposes. The only way to get this to work would be if a US is a square box/sphere while the SL is long enough that it doesn't get any + to SM from its width... but at the that point the SL vessel would be targeted at -2 from the front/back, rather than at the -1 given by SS. Looks like this may be one of those cases where the abstract nature of SS makes such an analysis break down... Quote:
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I would start with the mass, and give an estimate of how dense each type of component will be. Cargo holds the least, habitats next, etc.
There are some estimates of this sort on the Traveller forum. |
Re: Spaceships, Floor / Deck Plans, Volume and Hexes
I had the opportunity to visit a Russian sub in San Diego. And holy moly, but it was a claustrophobic experience. The crew was almost hundred, altogether, hot-bunking in small bunk beds, slotted into the walls with three beds stacked together, the lowest almost on the floor. I think there was only two toilets, too. Cramped corridors, bulkheads with circular openings just barely big enough for me to duck through without needing to try and slide through head first. So yeah, for very limited-space configuration warship, I could easily see three bunks in 2 m2, and those bunks hot-bunked (shared by 2 or even 3 crew-members, so that there is always someone sleeping there). So you could fit 6 - 9 people in 2 m2, and given that the ceiling wasn't too high either, it comes to less than 1 m3 per person. Add the narrow corridor in the middle and you are still well below 1.5 m3 per person.
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