01-14-2007, 12:55 PM | #11 | |||
Join Date: Aug 2004
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Re: [SPACE] Tidal braking
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Lunar tides: T = 1.6 million * (M * D-to-the-fourth) / (m * R-cubed) Satellite Orbital Period: P = 0.0588 * square root of (R-cubed/(M+m)) T: tidal forces; 1 represents Earth-like tides. P: orbital period of satellite in days M: mass of satellite in Earth masses m: mass of planet in Earth masses D: diameter of planet in Earth diameters R: radius of satellite's orbit in Earth diameters Solar tides: T = 0.3 * (M * D-to-the-fourth) / (m * R-cubed) Planetary Orbital Period: P = square root of (R-cubed/M) T: tidal forces; 1 represents Earth-like tides. P: orbital period in years M: mass of star in solar units D: diameter of planet in Earth diameters m: mass of planet in Earth masses R: radius of planet's orbit in AUs. I've included the associated orbital period calculations here because they become important later on. Quote:
Likewise, the same tidal forces that tend to slow a planet's rotation will also tend to drive satellites into higher orbits, eventually letting them break away from the planet. Younger systems will tend to have more satellites and in tighter orbits than older systems will. Quote:
Of course, the solar tides will be working to drive the satellite away from the planet at the same time that they're working to tide-lock the planet, with the twin side effects of lengthening the Satellite Orbital Period and weakening the lunar tidal effects. It may well be that planets never reach a point where lunar "tidal braking" puts up any significant opposition to solar tidal braking, because the solar tides will have driven the potential competition away first. If this is the case, it's likely that tide-locked worlds can't have satellites larger than asteroids, if that. Regardless, a tide-locked world will not be able to have a satellite with tidal forces equal to or stronger than the star's; the planet would have tide-locked to the satellite instead of the star. Second, a nitpick: Daylength doesn't equal 1/W; Rotational Period equals 1/W. The length of a day is computed from the Rotational Period on page 118, under "Local Calendar". |
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01-14-2007, 02:36 PM | #12 | ||||||
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
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Traumatic experiences…. Quote:
I don't think they are going to accept a corrigendum that increases the page count. However, it might be possible to decrease the axial tilt of planets with a high value of A * P/D^5) * S without making the rules on p. 118 too complicated. Quote:
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Decay is inherent in all composite things. Nod head. Get treat. Last edited by Agemegos; 01-24-2007 at 07:33 PM. |
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01-15-2007, 04:17 AM | #13 | ||||||||||||
Join Date: Aug 2004
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Re: [SPACE] Tidal braking
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I think that the best you're going to manage will be to provide online house rules. Quote:
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First, determine how long it will take for the planet's rotation to become synchronized with the satellite. If the age of the system is less than that, determine the actual rotational period by finding the total change in rotational speed over the full period and applying the same fraction of that as the fraction of the full period that has elapsed. (See the rules for determining a star's luminosity for an example of how to do this.) If the age of the system is greater than this point, use the same formula to determine how much longer it will take for the planet's rotational period to match the primary's rotational period, but subtract the square of the satellite's T from the square of the primary's T instead of adding it. If the difference of the T-squares is zero or negative, then the planet is tidally locked to the satellite. If it's positive, repeat the above age check to see if the planet has had time to become tide-locked to the sun; and if not, interpolate (as above) to determine what its current rotational speed is. If you have multiple satellites, arrange them in order of their orbital periods, from shortest to longest. As the planet's orbital period passes each one, move its T-squared from the plus column to the minus column and repeat the process until you reach the current age of the system, until the sum in the minus column equals or exceeds the sum in the plus column (at which point the planet is tidally locked to the last satellite to move into the minus column), or until all of them are in the minus column (at which point you go to the final step of determining solar tide-locking as above). The result is an iterative process, with one iteration for each satellite and a final iteration for the primary. Lengthy and potentially repetitive, but not particularly complicated. Quote:
Note that the Local Calendar section tends to break the rule-of-thumb of using the same letter to mean the same (sort of) thing throughout: it uses 'R' to mean "Rotational Period" instead of "Radius" and 'A' to mean "Apparent Period" instead of "Age". So the fact that you're using S to mean something not related to what the Local Calendar uses it for isn't a major crime. Given that, I'd be more inclined to use 'P' (some sort of period) instead of 'Daylength', rather than 'R' or 'S'. |
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01-15-2007, 04:54 AM | #14 | |||
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
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I'm getting flashbacks. I used to work for a freaking economic research bureau where the typesetters tried to stop the researchers from publishing equations in standard format. Quote:
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Decay is inherent in all composite things. Nod head. Get treat. |
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01-15-2007, 07:38 AM | #15 | |
Join Date: Oct 2004
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Re: [SPACE] Tidal braking
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And some of us others may lack the skills to do such stuff on our own, but are still interested and would appreciate it if we could read about it. |
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01-15-2007, 03:39 PM | #16 | |
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
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One of the roots of my dissatisfaction is that I am not a physicist but an economist, so work on orbital ballistics, tidal braking, and the climatic meteorology of tide-locked worlds is well outside my comfort zone. I do my best, but I'm very conscious that I might make errors. And I have about ten or fifteen points worth of psychological disadvantages having to do with my loathing of letting people be misled and misinformed. I hate to think that I might be publishing errors, and no-one will do so much as to check my algebra.
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Decay is inherent in all composite things. Nod head. Get treat. Last edited by Agemegos; 07-28-2007 at 09:27 AM. |
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01-15-2007, 05:43 PM | #17 | |
Wielder of Smart Pants
Join Date: Aug 2004
Location: Ventura CA
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Re: [SPACE] Tidal braking
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01-15-2007, 05:45 PM | #18 | |
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
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__________________
Decay is inherent in all composite things. Nod head. Get treat. |
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01-15-2007, 05:52 PM | #19 | |
Wielder of Smart Pants
Join Date: Aug 2004
Location: Ventura CA
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Re: [SPACE] Tidal braking
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01-15-2007, 06:02 PM | #20 | |
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
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__________________
Decay is inherent in all composite things. Nod head. Get treat. |
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Tags |
planets, space, system generation, tidal braking, tide, tide-locked, world generation |
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