06-19-2017, 09:07 AM | #1 |
Join Date: Jun 2017
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Wall Innate Attack - Encase the target?
Is it possible to create an Innate Attack + Wall (60%) to encase a target?
How much area to encase a normal size person? Thanks! Here's what I'm running: Force Wall (Innate Attack: Crush) 18 No Wounding, -50%; no die roll 2 points/level, +0%; Wall, +60%; Persistent , +40%; Area of Affect, 4 yards, +100%; No Blunt Trauma, -20%; Range 5x, +20%; No Knockback, -10%; Hovering, +10%; Magic, -10%. [87] |
06-19-2017, 09:57 AM | #2 |
Join Date: Jun 2013
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Re: Wall Innate Attack - Encase the target?
What you're looking for is the Binding Advantage, not some version of Innate Attack.
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06-19-2017, 10:45 AM | #3 |
Join Date: Aug 2005
Location: Saskatoon, SK, Canada
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Re: Wall Innate Attack - Encase the target?
I'd actually disagree, at least partially. While you can't use Innate Attack with Wall to hold someone immobile (that is, indeed, the realm of Binding), I don't see why you couldn't use a Wall to create a sphere with a person inside. They'd be able to move about within the sphere, attack it, and so forth, but the Wall can be created enclosing them, at least.
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06-19-2017, 10:11 PM | #4 |
Join Date: Jun 2017
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Re: Wall Innate Attack - Encase the target?
How much area to encase a normal size person?
I get 1x3x4 yards because of the AoE advantage (+100%). Is that correct? |
06-19-2017, 10:12 PM | #5 | |
Join Date: Jun 2013
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Re: Wall Innate Attack - Encase the target?
Quote:
Basically, what you'll need is to have the +60% version of Wall (the +30% one probably just lets you build a straight one that's only 4 yards tall), then fill up each hex surrounding the target. You'll stack another Wall on top of those, then fill the area between. Note this creates a dome, not a sphere - you'd have to create the Wall in the ground, which I don't think is an option.
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06-20-2017, 12:44 AM | #6 |
Join Date: Aug 2005
Location: Saskatoon, SK, Canada
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Re: Wall Innate Attack - Encase the target?
I agree that the default height for a Wall should be 4 yards. Personally, I think the +60% version of Wall should be enough to potentially trap someone with just one use, provided it's long enough - it says you can "form it into any shape you choose" at that level, and I think that's enough to allow you to reshape it into a circle, effectively. I would definitely require a big enough Wall to encircle the target without touching them, though. I think, for a standard human, that's going to require a 2-yard radius, large enough to make a 6-yard long wall. A single 1-yard radius Wall isn't quite enough to encircle a standard 1-yard hex.
Also, some can try to dodge out of this sort of thing as you cast it, with a Dodge and Drop - against a six-yard-long Wall, which effectively circles one hex, I'd give anyone a chance to dodge out, and even a wider circle could still potentially be dodgeable if someone had more than a 1-yard Step, thus allowing a longer Dodge and Drop. |
06-20-2017, 08:31 AM | #7 | |
Join Date: Jun 2017
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Re: Wall Innate Attack - Encase the target?
Quote:
So with the 12 yards of wall I have I could fully encase 2 adjacent people before they were hit by an attack? It's hard for me to visualize the math without hexes. I'd like to be able to save a crowd of people so maybe I'll drop the DR and get more area. Thanks! |
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06-20-2017, 08:42 AM | #8 |
Join Date: Aug 2005
Location: Saskatoon, SK, Canada
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Re: Wall Innate Attack - Encase the target?
Yeah, I'd allow it. I'd say that every 6 yards of Wall length translates to one hex you can encircle. So your 12 yards nicely covers 2 hexes (actually, every 6 yards covers something more like "a hex and a bit", and there should be some efficiencies since you're not actually fully encircling each hex anyway, but it works as a rule of thumb).
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06-20-2017, 09:00 AM | #9 | |
Join Date: Jun 2017
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Re: Wall Innate Attack - Encase the target?
Quote:
Does the wall advantage create 3 one yard cubes? Then added AoE multiples the number of cubes? |
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06-20-2017, 09:07 AM | #10 | |
Join Date: Jun 2013
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Re: Wall Innate Attack - Encase the target?
Quote:
*ProTip - the number of hexes at a specific distance is equal to 6x(radius-1), with 1 hex at radius 1. So 1 is 1, 2 is 6 (total 7), 3 is 12 (total 19), 4 is 18 (total 37), 5 is 24 (total 61), 6 is 30 (total 91), and so forth.
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Tags |
innate attack, wall |
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