05-20-2008, 11:33 PM | #31 |
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
No, dammit, that's not right. The unit for tidal range/amplitude in Space is the lunar tide on Earth, not the total tide. So the figure for lunar tide has to work out to 1.
Now let's see. Earth's diameter and density are both 1 by definition. The mass of the Moon is 0.0123, and the radius of its orbit is 30.16 Earth diameters. So T = x * (M * D)/(rho * R^3) 1 = x * (0.0123 * 1)/(1 * 30.16^3) x = 30.16^3 / 0.0123 = 2.23 million. T (lunar) = 2.23 million * (M * D)/(rho * R^3) All the variables are 1 by definition in the Solar tide on Earth, but since the tidal range unit is the Lunar tide not the total tide the coefficient ought to be 0.38, not 0.3.
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Decay is inherent in all composite things. Nod head. Get treat. Last edited by Agemegos; 05-20-2008 at 11:54 PM. |
05-20-2008, 11:50 PM | #32 |
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
As for tidal braking,my mistake with the unit of tidal height means that the sum of squares of tide heights on Earth is 1.14, not 0.58 as I thought.
<edit> Actually, it's 1.21. Earth's initial day length was about 12 hours, so it has lost 1 rotations/day over 4.5 billion years. E = (x * A * M/D^5) * sum of squares of tide heights 1 = (x * 4.5 * 1/1^5) * 1.14 x = 1 / (4.5 * 1.14) = 0.195 <edit> Correct result is 0.184 E = (0.195 * A * M/D^5) * sum of squares of tide heights <edit> Correct formula is E = (0.184 * A * M/D^5) * sum of squares of tide heights.</edit>
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Decay is inherent in all composite things. Nod head. Get treat. Last edited by Agemegos; 06-28-2008 at 02:57 AM. |
05-21-2008, 02:26 AM | #33 | |
Join Date: Sep 2004
Location: Manchester, UK
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Re: [SPACE] Tidal braking
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05-21-2008, 06:28 AM | #34 | |
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
Quote:
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05-21-2008, 09:01 AM | #35 | |
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Join Date: Apr 2008
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Re: [SPACE] Tidal braking
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05-21-2008, 11:22 AM | #36 | |
Join Date: Jan 2007
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Re: [SPACE] Tidal braking
Quote:
http://www.bautforum.com/ Not sure if that might be another place to get some feedback or not. >
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05-22-2008, 07:18 PM | #37 | |
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
Quote:
E = (0.195 * A * density/D^2) * sum of squares of tide heights
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Decay is inherent in all composite things. Nod head. Get treat. |
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05-23-2008, 05:42 AM | #38 | |
Join Date: Oct 2004
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Re: [SPACE] Tidal braking
Quote:
E = (0.195 * A * density/D^2) * (sum of squares of tide heights) to make a little bit more obvious where the brackets go. BTW, ease for typing into a pocket calculator is something that always interests me. |
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05-23-2008, 05:34 PM | #39 | ||
Join Date: May 2005
Location: Oz
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Re: [SPACE] Tidal braking
Quote:
E = (sum of squares of tide heights) * 0.195 * A * density / (D^2) Quote:
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05-29-2008, 08:00 PM | #40 |
Join Date: Aug 2004
Location: Maryland
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Re: [SPACE] Tidal braking
For those of you who have been following this:
I've finally found the time to start re-evaluating . . . well, pretty much the entirety of p. 117 of Space. I've got most of Agemegos' math in front of me and have been trying to confirm it, with some success already. I think he's on the right track even if I'm not sure of all the details yet. We may end up with a full-on rewrite of that page of the book. SJG errata coordinator tells me that this shouldn't present a problem, as long as we're satisfied that the results are correct.
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Jon F. Zeigler Base of operations for creative work is at Sharrukin's Palace. Fan fiction and other unproductive nonsense appears at FanFiction.Net. |
Tags |
planets, space, system generation, tidal braking, tide, tide-locked, world generation |
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