Steve Jackson Games - Site Navigation
Home General Info Follow Us Search Illuminator Store Forums What's New Other Games Ogre GURPS Munchkin Our Games: Home

Go Back   Steve Jackson Games Forums > Roleplaying > GURPS

Reply
 
Thread Tools Display Modes
Old 06-02-2019, 09:32 AM   #31
Ashtagon
 
Ashtagon's Avatar
 
Join Date: Jul 2009
Location: UK
Default Re: [Space] Mapping Large Flat Areas

Quote:
Originally Posted by Rupert View Post
I don't know the answer to this problem, but here's what I understand it to be:

We have a two-dimensional space (so x,y co-ordinates) upon which are scattered a large number of points, at random. How do we determine the average distance between closest neighbours?
The actual answer to this questions depends on two points:

1) How many stars are in this space?
2) What is the size of this space?

Without this information, the best answer you'll get is a complicated formula that requires calculus.
Ashtagon is offline   Reply With Quote
Old 06-02-2019, 06:26 PM   #32
AlexanderHowl
 
Join Date: Feb 2016
Default Re: [Space] Mapping Large Flat Areas

There are around 2,000 stars within 50 ly of Sol, many of which would appear quite close to each other on a 2D map without a 3D dimension. There are ~260,000 stars within 250 ly of Sol, many of which would appear quite close to each other on a 2D map without a 3D dimension. In the former case, there would effectively be effectively 1 star per 4 square ly of projection. In the latter case, there would effectively be 3 stars per 4 square ly of projection. You can start to see the complications with a 2D hyperspace real quickly, and that is without looking at the millions of galaxies below and above the Milky Way.
AlexanderHowl is online now   Reply With Quote
Old 06-03-2019, 05:41 AM   #33
Agemegos
 
Agemegos's Avatar
 
Join Date: May 2005
Location: Oz
Default Re: [Space] Mapping Large Flat Areas

Quote:
Originally Posted by Ashtagon View Post
The actual answer to this questions depends on two points:

1) How many stars are in this space?
2) What is the size of this space?

Without this information, the best answer you'll get is a complicated formula that requires calculus.
I gave the formula in post #19. It's not complicated and doesn't require calculus. Average nearest-neighbour distance in two Euclidean dimensions = 0.5/sqrt(n/V).
__________________
copyright Brett Evill
FLAT BLACK discussion group at tekeli.li
On-line texts at flatblack.wikidot.com

Last edited by Agemegos; 06-03-2019 at 09:13 PM.
Agemegos is online now   Reply With Quote
Reply

Tags
mapping, space

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Fnords are Off
[IMG] code is Off
HTML code is Off

Forum Jump


All times are GMT -6. The time now is 07:49 PM.


Powered by vBulletin® Version 3.8.9
Copyright ©2000 - 2019, vBulletin Solutions, Inc.