12-11-2017, 10:32 AM | #11 | ||
Join Date: Jul 2008
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Re: [Spaceships] Breaking orbit with a low-thrust drive
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There's very little flexibility about the shape of an orbit. In particular... Quote:
An orbit (well, around a single gravitaitonal point source, but close enough) is elliptical. It can't be 'egg-shaped'. One of the two (equally) narrow ends is the closest point to the orbited body, the other is the farthest.
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12-11-2017, 10:53 AM | #12 |
Join Date: Aug 2007
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Re: [Spaceships] Breaking orbit with a low-thrust drive
Oh no. Egg-shaped orbits are a real thing. Spy sats use them.
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Fred Brackin |
12-11-2017, 10:55 AM | #13 | |
Join Date: May 2010
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Re: [Spaceships] Breaking orbit with a low-thrust drive
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12-11-2017, 11:04 AM | #14 | |
Join Date: Jul 2008
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Re: [Spaceships] Breaking orbit with a low-thrust drive
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some satellites use significantly eccentric elliptical orbits to get long dwell times around their apoapsis. But such an orbit does not have a big/little end distinction - both ends are narrow, one is near the planet (and thus passed through fast) the other is far away.
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I don't know any 3e, so there is no chance that I am talking about 3e rules by accident. |
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12-11-2017, 11:05 AM | #15 |
Join Date: Mar 2013
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Re: [Spaceships] Breaking orbit with a low-thrust drive
While "egg-shaped" is used colloquially for elliptical orbits, it's still true that the shape of the orbit at periapsis and apoapsis is identical. Only the velocity differs.
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12-11-2017, 12:03 PM | #16 | |
Join Date: Sep 2013
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Re: [Spaceships] Breaking orbit with a low-thrust drive
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In rocket science, one does not simply "thinK". One does the math and checks the delta V. |
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12-11-2017, 12:26 PM | #17 |
Join Date: Aug 2008
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Re: [Spaceships] Breaking orbit with a low-thrust drive
Using constamt low acceleration, you'll end up slowly spiraling outward from the planet until you reach escape velocity. The delta-v needed should roughly be the difference between your current average orbital velocity and escape velocity. You aren't using the Oberth effect to get extra oomph from your burns, so there's nothing special going on here. The lwngth of time ahould be, in seconds, dv/acceleration,with 1G = 9.81, and velocity measured in m/s. 1 m/s is about 1609.334. Thus, in GURPS units, it takes about 0.006095 * dv/acceleration seconds to break orbit.
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12-11-2017, 12:43 PM | #18 | ||
Join Date: Jul 2008
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Re: [Spaceships] Breaking orbit with a low-thrust drive
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My own calculation confirms what Anthony said back on the first page: Quote:
EDIT: I shouldn't have said "nothing will be cheaper" - I haven't checked whether it's possible for a retrograde burn to lower your periapsis prior to doing an escape burn could be efficient. Seems unlikely, but my intuition isn't reliable.
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I don't know any 3e, so there is no chance that I am talking about 3e rules by accident. Last edited by Ulzgoroth; 12-11-2017 at 12:51 PM. |
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12-11-2017, 12:45 PM | #19 | |
Join Date: Feb 2005
Location: Berkeley, CA
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Re: [Spaceships] Breaking orbit with a low-thrust drive
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Your final loop involves an extremely elliptical orbit (escape velocity is 11.2 km/s, so your velocity at bottom of loop starts out at 11.15 km/s). This orbit has 110x the semi-major axis of a circular orbit, and thus takes a bit over a thousand times as long (around 1500 hours), which you probably do not want to do. However, it's really only the last few loops that are horribly inefficient. |
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12-11-2017, 02:14 PM | #20 | |
Join Date: Apr 2015
Location: Pennsylvania
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Re: [Spaceships] Breaking orbit with a low-thrust drive
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The Oberth effect is important, but it's not an on-or-off thing. Simply put, in lower orbits you are faster, and have more momentum (including your reaction mass), and therefore can get more of a momentum change from your reaction mass. |
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