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12-19-2014, 08:47 PM | #1 |
Join Date: Oct 2012
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Linear shaped charge to cut through DR 1900?
Anyway, in the field of weapon design I need a linear shaped charge (manually placed) to cut through starship armor, which could be as much as DR 1900. It can't just make a hole, it has to cut through it along its length. The idea is to string a bunch of them together (rigid sections) in a circle to blast a large opening through an armored airlock hatch. (The pressure door gets the armor's full DR to protect it, as it's on the other side.) Obviously it's going to be heavy, rigid and short, but it doesn't need any more portability than somebody being able to carry it from the storeroom to the airlock. It'll take a bunch of sections to make a man sized hole, of course.
What I'm wondering is how much it would weigh per foot, so I can get some idea of the size, weight and number of sections. It will do maximum damage automatically, and if it gets the (10) armor divisor, instead of the (5) armor divisor the flexible but much smaller cord of the same basic thing from High Tech gets, (which weighs 0.5 lb per foot), it would need to do 6dx6(10). If it's stuck with the (5) divisor, then it would be closer to 6dx11 (5). Which going by the "Blowing stuff up" section of Basic and scaling (assuming the charge from High Tech is the equivalent of .11 lb TNT), would be 137 lb or so for a 1ft section. Which is outrageous. If it gets to do 6dx6 (10), again scaling, it would weigh 41 lb for a 1ft section. Which is actually pretty close to what I had imagined for a 1 or 2 foot section. So use the 6dx6(10) scaling, and 41 lb per foot long section? Or would it be better to use one smaller charge to cut partway through, then place another one in the same sport to finish the job, or would that not work with shaped charges at all? |
12-19-2014, 09:20 PM | #2 |
Join Date: Sep 2007
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Re: Linear shaped charge to cut through DR 1900?
Per B415, a 6dx6 explosion takes 6x6 / 4 = 9 lbs of TNT. Divide by the REF of your futuristic explosive. 6dx11 would be 11^2 / 4 = 30 lbs. I think the charges are smaller than your calculations suggest.
This doesn't seem far out of line, as the rounds for the 120mm tank gun on the Abrams weigh about 50 lbs, which includes the propellent and case, and not just the warhead. A shaped charge works by focusing its energy into a small jet (often assisted by lining the explosive with a liner of metal (or techy whatever) to be vaporized and propelled. (See this pic.) The hole it makes is much smaller than the actual charge, so you couldn't tunnel through with a bunch of the same charge. They wouldn't fit into the hole. You might be able to dig a little deeper in the same hole, but my understanding is that the proper standoff distance is also important. |
12-19-2014, 09:35 PM | #3 | |
Join Date: Oct 2012
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Re: Linear shaped charge to cut through DR 1900?
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12-19-2014, 11:04 PM | #4 |
Join Date: Jul 2012
Location: A crappy state called Illinois
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Re: Linear shaped charge to cut through DR 1900?
Assuming that the linear shape-charge in High-Tech uses C4 as it's explosive filler, then even if you use meta-stable hydrogen (REF6) it'll just up the damage to 6d but I would agree that it wouldn't be far off to say that advances had been made that give it an AD of 10.
So in this case, assuming an REF of 6 (which is about as good as it's gonna to get barring super science or nukes), you'd need a cord that weighed about 14lbs per foot so I think that some kind of energy weapon based cutter might be a better idea at this point. DR 1900 is pretty beefy.
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12-20-2014, 03:10 AM | #5 |
Join Date: Nov 2014
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Re: Linear shaped charge to cut through DR 1900?
if time permits, wouldnt some kinda thermal charge work better ?, reading up on the rules for thermal lances, i see that they treat materials as ablative or semi-ablative, in that case it would first eat up the DR and then start to chew its way through the hull itself, if breaching has to be fast, try a EFP ?, you have a tripod that you place on the hull, putting the EFP at the proper distance, then you detonate it and it punches through making a Mouse hole for entry
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12-20-2014, 03:15 PM | #6 | |
Join Date: Oct 2012
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Re: Linear shaped charge to cut through DR 1900?
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And that's thing - it's only going to be used cut through starship airlock armor from the airlock of another starship or boat. Likely get several guys to move a pile of them maybe the 50-100 feet at most from the storeroom (where they will always be, sitting in a box, right up until the time to use them comes), to the airlock or boat deck, not remotely under fire, then spend a minute or two setting the charges, set a time fuze and back the ship off several meters, then board the enemy ship. It's not designed to be something carried by soldiers, or anybody else, on a daily basis. As long as it weighs 33 pounds, a crewman or marine can carry two of them at a time to where they're needed, and several guys will be running them, and they won't be carrying other equipment at the same time, they can just set it down for they're doing it. It'll take a bunch of them, 20 sections for a 4ft x 6ft hole, but there's room for them on a starship. There would also be on maybe a second's longer delay a big plain HE charge in the middle of the armored plug door to knock it over. I wonder if you would need corner sections, or just initially blow a single charge extending past where you want it, then the main charges would extend past that. The downside is that the time required generally is enough time set up a hot reception on the other side. The defenders have the option of whether the inner airlock door (several feet past what we just blew up) is going to be open or closed. Open gives you a clear field of fire for the MG positions you've set up, but also exposes them to fire from heavy weapons from the attacker's ship. Also likely is another set of smaller charges for less well armored ships like frigates, cruisers and destroyers. The advantage would be being able to get through it faster, with fewer, longer and lighter sections. Also, going back to the 105mm recoilless rifle, 6dx7 shell impact damage will actually punch through a DR 70 bulkhead without needing an armor divisor at all. Maybe just a strengthened shell with no armor divisor, slightly less powerful blast and fragmentation, and a base fuze? Also an actual AP shell in case they armored the target, but that would have far less effect on the other side. |
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12-20-2014, 04:03 PM | #7 |
Join Date: Oct 2012
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Re: Linear shaped charge to cut through DR 1900?
Hang on, I don't know what I did for scaling last time, but this time around, assuming 1.7 instead of listed 1.4 like last time, I would up with just 20 lb for a foot long section that does 6dx6(10). (It will always inflict maximum damage as a contact explosion.)
Possibly light enough for a few of them to go with a landing party. Won't go through the front of a modern MBT (DR 1680, doubled versus shaped charges), but will go through the side (a little less than half that). As a foot long line instead of a pencil sized jet, it's going to do a heck of a lot more damage on the other side, easily knocking it out. Going for a 5dx5 (10) section, useful against all cruisers, I wound up with just 10 lb for a 1 foot long section, or more accurately it will be 20 lb for a 2 foot long section. |
12-20-2014, 07:05 PM | #8 | |
Join Date: Oct 2013
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Re: Linear shaped charge to cut through DR 1900?
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Tags |
armor divisor, explosive, explosives required, shaped charge, weapon design |
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