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Langy · 07-16-2012, 12:09 PM

I'd do Hardened as dividing the armor divisor, personally. That way a (2) AD hit by something with the first level of Hardened would be (2)/2 = (5)1. Something with a (10) AD and that same level of Hardened would be (10)/2 = (5). Etc.

07-16-2012, 12:09 PM	#3
Langy Join Date: May 2008 Location: CA	Re: Continuous Armor Divisors I'd do Hardened as dividing the armor divisor, personally. That way a (2) AD hit by something with the first level of Hardened would be (2)/2 = (5)1. Something with a (10) AD and that same level of Hardened would be (10)/2 = (5). Etc.