Steve Jackson Games Forums - View Single Post

AlexanderHowl · 11-27-2019, 04:07 PM

I generally use a volumetric analysis, with the density of liquid hydrogen as the baseline, for massive installations). If we assume Mimas as an example of a small moon, we have a volume of 32 million cubic kilometers. A comparable Death Star could be 1 quadrillion tonnes to 3 quadrillion tonnes, depending on density.

If we go with 3 quadrillion tonnes, the result is a more modest SM+27. The spinal battery would have a 3 YJ release (assuming cosmic energy), which ends up being 6d×100,000 d-damage, which is about 1% the damage required to destroy a planet. You would need around a million times the energy.

11-27-2019, 04:07 PM	#6
AlexanderHowl Join Date: Feb 2016	Re: Death Star Spaceship I generally use a volumetric analysis, with the density of liquid hydrogen as the baseline, for massive installations). If we assume Mimas as an example of a small moon, we have a volume of 32 million cubic kilometers. A comparable Death Star could be 1 quadrillion tonnes to 3 quadrillion tonnes, depending on density. If we go with 3 quadrillion tonnes, the result is a more modest SM+27. The spinal battery would have a 3 YJ release (assuming cosmic energy), which ends up being 6d×100,000 d-damage, which is about 1% the damage required to destroy a planet. You would need around a million times the energy.