Quote:
Originally Posted by Gumby Bush
Per RAW, the only benefit is covering another side hex.
I might go with:
DB = largest + sum(applicable to that hex)/5
A peshkali with 6 large (DB 3) shields would get DB 3 + (5*3)/5 = DB 6.
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I like this. Makes it so a peshkali with 6 DB0 bucklers gets nothing extra. Also, a peshkali with 6 large shields
should be incredibly well covered.