Re: [Spaceships] simply fuel math...
Quote:
Originally Posted by TGLS
OK, if you want something more accurate, but more fiddly, then I think this is right. Take the natural logarithm of 20 divided by 20 minus the number of fuel tanks and divide by 0.05 (ln(20/(20tanks))/0.05). This gives you the effective number of fuel tanks for that particular drive, so calculate your delta V from there.

It's probably simpler to describe "divide by 0.05" as "multiply by 20".
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I don't know any 3e, so there is no chance that I am talking about 3e rules by accident.
