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Old 10-03-2017, 11:27 PM   #9
Join Date: Jul 2008
Default Re: [Spaceships] simply fuel math...

Originally Posted by TGLS View Post
OK, if you want something more accurate, but more fiddly, then I think this is right. Take the natural logarithm of 20 divided by 20 minus the number of fuel tanks and divide by 0.05 (ln(20/(20-tanks))/0.05). This gives you the effective number of fuel tanks for that particular drive, so calculate your delta V from there.
It's probably simpler to describe "divide by 0.05" as "multiply by 20".
I don't know any 3e, so there is no chance that I am talking about 3e rules by accident.
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